Click to See Complete Forum and Search --> : need help step 2 of file upload


woodward2415
09-07-2006, 11:53 AM
ok....... I'm going crazy trying to figure this out!!! :)

I have been following steps in previous post on how to insert file upload into html.

I can do this part... but the second part where you tell the picture to upload to, I can't get to work! :confused:


do i start a whole new webpage and insert the following html to tell it where to upload (and when I do this.... what parts of this do I change/add my particular info and what is it I am adding??? Hope some of this makes sense!

:

</html>

<?php

// filename: upload.processor.php

// first let's set some variables

// make a note of the current working directory, relative to root.
$directory_self = str_replace(basename($_SERVER['PHP_SELF']), '', $_SERVER['PHP_SELF']);

// make a note of the directory that will recieve the uploaded file
$uploadsDirectory = $_SERVER['DOCUMENT_ROOT'] . $directory_self . 'uploaded_files/';

// make a note of the location of the upload form in case we need it
$uploadForm = 'http://' . $_SERVER['HTTP_HOST'] . $directory_self . 'upload.form.php';

// make a note of the location of the success page
$uploadSuccess = 'http://' . $_SERVER['HTTP_HOST'] . $directory_self . 'upload.success.php';

// fieldname used within the file <input> of the HTML form
$fieldname = 'file';

// Now let's deal with the upload

// possible PHP upload errors
$errors = array(1 => 'php.ini max file size exceeded',
2 => 'html form max file size exceeded',
3 => 'file upload was only partial',
4 => 'no file was attached');

// check the upload form was actually submitted else print the form
isset($_POST['submit'])
or error('the upload form is neaded', $uploadForm);

// check for PHP's built-in uploading errors
($_FILES[$fieldname]['error'] == 0)
or error($errors[$_FILES[$fieldname]['error']], $uploadForm);

// check that the file we are working on really was the subject of an HTTP upload
@is_uploaded_file($_FILES[$fieldname]['tmp_name'])
or error('not an HTTP upload', $uploadForm);

// validation... since this is an image upload script we should run a check
// to make sure the uploaded file is in fact an image. Here is a simple check:
// getimagesize() returns false if the file tested is not an image.
@getimagesize($_FILES[$fieldname]['tmp_name'])
or error('only image uploads are allowed', $uploadForm);

// make a unique filename for the uploaded file and check it is not already
// taken... if it is already taken keep trying until we find a vacant one
// sample filename: 1140732936-filename.jpg
$now = time();
while(file_exists($uploadFilename = $uploadsDirectory.$now.'-'.$_FILES[$fieldname]['name']))
{
$now++;
}

// now let's move the file to its final location and allocate the new filename to it
@move_uploaded_file($_FILES[$fieldname]['tmp_name'], $uploadFilename)
or error('receiving directory insuffiecient permission', $uploadForm);

// If you got this far, everything has worked and the file has been successfully saved.
// We are now going to redirect the client to a success page.
header('Location: ' . $uploadSuccess);

// The following function is an error handler which is used
// to output an HTML error page if the file upload fails
function error($error, $location, $seconds = 5)
{
header("Refresh: $seconds; URL=\"$location\"");
echo '<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN"'."\n".
'"http://www.w3.org/TR/html4/strict.dtd">'."\n\n".
'<html lang="en">'."\n".
' <head>'."\n".
' <meta http-equiv="content-type" content="text/html; charset=iso-8859-1">'."\n\n".
' <link rel="stylesheet" type="text/css" href="stylesheet.css">'."\n\n".
' <title>Upload error</title>'."\n\n".
' </head>'."\n\n".
' <body>'."\n\n".
' <div id="Upload">'."\n\n".
' <h1>Upload failure</h1>'."\n\n".
' <p>An error has occured: '."\n\n".
' <span class="red">' . $error . '...</span>'."\n\n".
' The upload form is reloading</p>'."\n\n".
' </div>'."\n\n".
'</html>';

matty_y2002
09-07-2006, 03:35 PM
hey, i think this will solve your problem, well it worked for me!

The $path is where the picture/image will be stored, make sure you have this folder created already. and userfile is the name of the input="file" in your html code e.g <input type="file" name="userfile"/>

$path = "./uploads/";
$res = copy($HTTP_POST_FILES['userfile']['tmp_name'], $path.

$HTTP_POST_FILES['userfile']['name']);

Hope this has helped :)