luke2125
04-17-2007, 01:34 PM
Hi there,
Could someone please tell me what's wrong with this code, it's a search engine that I would like to search for a specific zip code and display the results. I would appreciate any help regarding this matter:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN"
"http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<title></title>
</head>
<body>
<h2>Search</h2>
<form name="search" method="post" action="<?=$PHP_SELF?>">
Seach for: <input type="text" name="find" /> in
<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>
<?php
//This is only displayed if they have submitted the form
if ($searching =="yes")
{
echo "<h2>Results</h2><p>";
//If they did not enter a search term we give them an error
if ($find == "")
{
echo "<p>You forgot to enter a search term";
exit;
}
// Otherwise we connect to our Database
mysql_connect("", "", "") or die(mysql_error());
mysql_select_db("") or die(mysql_error());
// We preform a bit of filtering
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);
//Now we search for our search term, in the field the user specified
$data = mysql_query("SELECT * FROM clinics WHERE Zip LIKE LIKE '%$find%' ");
//And we display the results
while($result = mysql_fetch_array( $data ))
{
echo $result['Name'];
echo " ";
echo $result['Address'];
echo "<br>";
echo $result['Zip'];
echo "<br>";
echo "<br>";
}
//This counts the number or results - and if there wasn't any it gives them a little message explaining that
$anymatches=mysql_num_rows($data);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query<br><br>";
}
//And we remind them what they searched for
echo "<b>Searched For:</b> " .$find;
}
?>
I think the problem likes in the SELECT statement, nothing comes out, just the form, I put in a number(zip code) and nothing comes out.......Thanks and God Bless.....
Could someone please tell me what's wrong with this code, it's a search engine that I would like to search for a specific zip code and display the results. I would appreciate any help regarding this matter:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN"
"http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<title></title>
</head>
<body>
<h2>Search</h2>
<form name="search" method="post" action="<?=$PHP_SELF?>">
Seach for: <input type="text" name="find" /> in
<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>
<?php
//This is only displayed if they have submitted the form
if ($searching =="yes")
{
echo "<h2>Results</h2><p>";
//If they did not enter a search term we give them an error
if ($find == "")
{
echo "<p>You forgot to enter a search term";
exit;
}
// Otherwise we connect to our Database
mysql_connect("", "", "") or die(mysql_error());
mysql_select_db("") or die(mysql_error());
// We preform a bit of filtering
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);
//Now we search for our search term, in the field the user specified
$data = mysql_query("SELECT * FROM clinics WHERE Zip LIKE LIKE '%$find%' ");
//And we display the results
while($result = mysql_fetch_array( $data ))
{
echo $result['Name'];
echo " ";
echo $result['Address'];
echo "<br>";
echo $result['Zip'];
echo "<br>";
echo "<br>";
}
//This counts the number or results - and if there wasn't any it gives them a little message explaining that
$anymatches=mysql_num_rows($data);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query<br><br>";
}
//And we remind them what they searched for
echo "<b>Searched For:</b> " .$find;
}
?>
I think the problem likes in the SELECT statement, nothing comes out, just the form, I put in a number(zip code) and nothing comes out.......Thanks and God Bless.....