Counting in a string

[firman]

Say I have

$file = me/you/this/that/open.php


How can I count how many / are in a string?


Or better yet... how can I replace the words in between the / with ..

?

[ellisgl]

Opps

[firman]

That will only give me the position of the / not how many there are

[ellisgl]

Opps - thinking here try this:

<?php
$text = split('/',$file);
$count = count($text);
echo $count;
?>

[ellisgl]

As for the replacement use http://www.php.net/preg_replace - I'm not good with regexp..

[sitehatchery]

//1st question
$file = 'me/you/this/that/open.php';
$arr=explode('/', $file);
$count=count($arr)-1;
echo $count;

echo "<br>";

//2nd question
$val=array('what', 'is', 'your', 'last', 'name.php');
echo implode('/', $val);

[firman]

How about to replace the words in the file?

[ellisgl]

if you have your stuff in an array - you could search the array for what you want if it has to be dynamic - get the key - update that key - combine and there you go.

if you know the key then you could just do $arr[5] = 'monkey';

[sitehatchery]

ok, in the file itself.


$base='/me/you/this/that/';
$old='open.php';
$new='closed.php';

if(is_file($base.old){
copy($base.$old, $base.$new);
unlink($base.$old);
}

[firman]

Sitehatchery?

What yours does above is not what I want?

I want to change whateve is inbetween the slashes to ..

[sitehatchery]

How about to replace the words in the file?

You said the "words in the file". From this, I thought maybe you were referring to changing the name of the file itself. The derived meaning was a guess and I only had a couple minutes to spit out a solution.

[firman]

Any idea on how to change what is between slashes to .. ?

[NogDog]

$file = 'me/you/this/that/open.php';
$dots = preg_replace('#[^/]+/#', '../', $file);
echo $dots;

Outputs:
../../../../open.php

[MrCoder]

What is the difference between using "/" or "#" in preg?

Is '#[^/]+/#' different to '/[^/]+//'?

[NogDog]

What is the difference between using "/" or "#" in preg?

Is '#[^/]+/#' different to '/[^/]+//'?
There is no functional difference, other than that by selecting "#" as my regex delimiter, I now do not have to escape the "/" characters in the pattern, making it just a bit less to type and more importantly easier to read. If I had used '/' as the delimiter, then the regex would have been:

'/[^\/]+\//'