Cubic root

[philonline]

I'm trying to calculate the Cubic root of an operation... wich syntax should I use?

:confused:

Thanx

Phil

[96turnerri]

cbrt should do the trick :D

[pyro]

What is cbrt? :confused:

[96turnerri]

its the multiplier instead of a simple calculation say 1 x 2, or 3 + 5, do 2 cbrt 8

[Charles]

<script type="text/javascript">
<!--
Math.cbrt = function (n) {return Math.pow(n, 1/3)}

alert (Math.cbrt(27))
// -->
</script>

[pyro]

Originally posted by 96turnerri
its the multiplier instead of a simple calculation say 1 x 2, or 3 + 5, do 2 cbrt 8 There isn't, however, any default function called cbrt to get the cubic root. Charles solution is what you want.

[96turnerri]

i presumed he already had the script just wanted the command/function to get cubic root and that is cbrt, not doing all the work for him :p

[pyro]

Since one would have to make the function before the use it, they could name it whatever they want. Wouldn't have to name it cbrt.

[96turnerri]

ok do a search on google for javascript cubic root code, all of the results give cbrt not cubicroot or anything else

[pyro]

My point is that there is no function to do this. Who cares what people name the functions that they create? It is not important... Telling them:Originally posted by 96turnerri
cbrt should do the trick :D really doesn't help much...

[96turnerri]

ok whatevr m8, im tired and going to bed, site looks good btw

[philonline]

Originally posted by 96turnerri
i presumed he already had the script just wanted the command/function to get cubic root and that is cbrt, not doing all the work for him :p

Quite right, that is!

Thanx you all for your interest in my beginners stupid questions. After trying out all the different solutions the simplest one is

pow (n, 1/3)

if this can interest anybody.

Phil

[Charles]

Originally posted by philonline
Quite right, that is!

Thanx you all for your interest in my beginners stupid questions. After trying out all the different solutions the simplest one is

pow (n, 1/3)

if this can interest anybody.

Phil Like I demonstrated above.