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GlitchKing
10-31-2009, 10:33 AM
Hey,

Anyone know how to make images appear in a created function like this.

ImageTTFText ($im, 12, 0, 300, 20, $title, $font ,"Latest Glitches");

I want it to generate an image inside another image.

My main image
http://www.glitcher.net/sig.png/

Generated Image
http://img.youtube.com/vi/J875J27q-2k/1.jpg

Thanks,

GlitchKing
10-31-2009, 10:42 AM
Here is my script.

//SETTINGS
$image = "test.png"; //Background
$font = "GOODTIME.ttf"; //Font (tmp)
$sitename = $settings['sitename']; //Site Name
$version = $settings['version']; //Site Version



$im = imagecreatefrompng($image);
$tc = ImageColorAllocate ($im, 80, 80, 80);
$red = ImageColorAllocate ($im, 250, 0, 0);
$blue = ImageColorAllocate ($im, 0, 0, 250);
$title = ImageColorAllocate($im, 132, 0, 0);

$result = dbquery("SELECT * FROM `" . DB_PREFIX . "articles` INNER JOIN `" . DB_PREFIX . "article_cats` ON article_cat=article_cat_id ORDER BY `article_id` DESC LIMIT 0 , 16");
if (dbrows($result)) { while ($data = dbarray($result)) {
$glitch=(trimlink($data['article_cat_name'], 12))." - ".(trimlink($data['article_subject'],20));
$date=showdate("%m.%d.%y", $data['article_datestamp']);
}

ImageTTFText ($im, 12, 0, 300, 20, $title, $font ,"Latest Glitches");
header("Content-Type: image/png");
Imagepng($im);
ImageDestroy ($im);