onmouseout function

[insight]

Hi everyone--
Could you please direct your attention to http://insightfulart.com/DanaSmith/

The page (beyond the splash screen) has frames. The buttons on the left load a page in the central frame when they have onmouseover. Now, here's what I want to to do:

when the button has onmouseout, should turn back to the white page. Easy enough to do, right?

However, here's the catch. When the image is CLICKED, the onmouseout function should NOT happen. It should only happen if the image is not clicked.

Obviously this requires a function of sorts, of which I have no clue to do. Can somebody please help me code this?

Thanks,
-Sriram

[havik]

Insert this into the link tags:

onMouseOut="window.open('original/preview.html', 'CONTENT')">

Where "original/preview.html" will be your white page

Try that.

Havik

[insight]

Hi Havik-
That only solves half the problem... If I do that, then when the person moves their mouse away from the image, it reverts back to white. However, if the user clicks on the graphic, then the onmouseover event should not happen.

Thanks,
-Sriram

[DrDaMour]

you'll have to set some type of sentinel eg:

onmouseclick="clicked=1" and onmouseout="if (clicked != 1) { do mouse out event;clicked=0}"

[insight]

Hey--
Where do I add those snippets to the page?

Thanks,
-Sriram

[DrDaMour]

in the image tag, anything beyond that is really out of the scope of a help forum, and you probably need to learn some programming basics.

[DrDaMour]

yeah, it's onclick="click events" not onmouseclick, i always funk that one up