rutledj
12-07-2005, 07:43 PM
I'm trying to display some data with a checkbox beside it. I don't think I have the single/double qoutes correct. Perhaps someone could explain.
Here is the code:
<?php
require_once('./db/mysql_connect.php');
$query = "SELECT * FROM prayerconcerns order by person";
$result = @mysql_query ($query);
$num_rows = mysql_num_rows ($result);
if ($num_rows > 0)
{
{
echo '<input type="checkbox" name="$row[0]"   value="$row[1]"';
}
mysql_free_result ($result);
mysql_close(); //close the database connection.
}
?>
All it does is displays a checkbox with nothing after it. $row[0] contains an id number and $row[1] contains a name.
Thanks,
Rut
Here is the code:
<?php
require_once('./db/mysql_connect.php');
$query = "SELECT * FROM prayerconcerns order by person";
$result = @mysql_query ($query);
$num_rows = mysql_num_rows ($result);
if ($num_rows > 0)
{
{
echo '<input type="checkbox" name="$row[0]"   value="$row[1]"';
}
mysql_free_result ($result);
mysql_close(); //close the database connection.
}
?>
All it does is displays a checkbox with nothing after it. $row[0] contains an id number and $row[1] contains a name.
Thanks,
Rut