force image to download not to display in browser

How can I force an image to be downloaded but not displayed in the browser window?

How can I force an image to be downloaded but not displayed in the browser window?

Put this in the head of your page.

Code:

---

<script type="text/javascript">
var img1 = new Image();
img1.src = 'path/to/your/image.gif';
</script>

---

This will cache the image in your temporary internet files folder, but won't display it until you want to.

Opps, bit of a bobo, meant to reply to the guy who was asking about file download in php. I have no idea how you force a download using JS.

In PHP use header - use octet stream rather than file type (eg jpg)
This together with content disposition will correctly force download for a document/image etc.

Caution: absolutely do not allow the file to be choosen using $_GET['file'] without cleaning $_GET['file'] first.

PHP Code:

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        //set the content as octet-stream    
        header("Content-Type: application/octet-stream");    //
        // tell the thing the filesize
        header("Content-Length: " . filesize($download_path.$file));    
        // set it as an attachment and give a file name
        header('Content-Disposition: attachment; filename='.$file);
        // read into the buffer
        readfile($download_path.$file); 


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See you posted this under js as well. Here's the PHP reply.

In PHP use header - use octet stream rather than file type (eg jpg)
This together with content disposition will correctly force download for a document/image etc.

Caution: absolutely do not allow the file to be choosen using $_GET['file'] without cleaning $_GET['file'] first.

PHP Code:

---

        //set the content as octet-stream    
        header("Content-Type: application/octet-stream");    //
        // tell the thing the filesize
        header("Content-Length: " . filesize($download_path.$file));    
        // set it as an attachment and give a file name
        header('Content-Disposition: attachment; filename='.$file);
        // read into the buffer
        readfile($download_path.$file); 


---

This is what I use:

download.php:

PHP Code:

---

<?php
// Force download of image file specified in URL query string and which
// is in the same directory as this script:
if(!empty($_GET['img']))
{
   $filename = basename($_GET['img']); // don't accept other directories
   $size = @getimagesize($filename);
   $fp = @fopen($filename, "rb");
   if ($size && $fp)
   {
      header("Content-type: {$size['mime']}");
      header("Content-Length: " . filesize($filename));
      header("Content-Disposition: attachment; filename=$filename");
      header('Content-Transfer-Encoding: binary');
      header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); 
      fpassthru($fp);
      exit;
   }
}
header("HTTP/1.0 404 Not Found");
?>

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usage:

HTML Code:

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<img src="/images/download.php?img=imagename.jpg" alt="test">

---

@haroon373,
Don't double post. If you can't get an answer in one, state it and open a different one. The two have been merged.

Hello,
I used this code and it works great.

http://gottweeters.com/follow-me-buttons

Thanks NogDog!

Quote:

---

Originally Posted by NogDog

This is what I use:

download.php:

PHP Code:

---

<?php
// Force download of image file specified in URL query string and which
// is in the same directory as this script:
if(!empty($_GET['img']))
{
   $filename = basename($_GET['img']); // don't accept other directories
   $size = @getimagesize($filename);
   $fp = @fopen($filename, "rb");
   if ($size && $fp)
   {
      header("Content-type: {$size['mime']}");
      header("Content-Length: " . filesize($filename));
      header("Content-Disposition: attachment; filename=$filename");
      header('Content-Transfer-Encoding: binary');
      header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); 
      fpassthru($fp);
      exit;
   }
}
header("HTTP/1.0 404 Not Found");
?>

---

usage:

HTML Code:

---

<img src="/images/download.php?img=imagename.jpg" alt="test">

---

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