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I keep having new questions so I'm starting this thread to neatly keep them all together. That's ok, I think? I hope I'm not asking too many questions :eek:
What I'm wondering right now is if I make a class--let's say User--and put it in a file--user.class.php--should any children of that class go in that file or should they have their own? Like Login could extend that class, Signup could, etc. Should they be in login.class.php and signup.class.php, respectively?
I normally keep them in separate files. This is particularly useful if you want to use an __autoload() function to take care of loading class definitions (which, however, requires a consistent naming convention so that your __autoload() function can figure out where a class's file is based on the class name).
PS: I'd probably have a User class (basically a data model class) and a separate UserAuth class (basically a controller-type class) with login() and register() methods which may accept and/or return a User object as applicable (i.e., using composition instead of inheritance in this case), since log-in and register are actions, not things, so you can't really say that "Login is a User" or "Register is a User."
user register, login, auth, changepass, etc.. should all be in the same class.
splitting them up has no benefit, having signup/login/register/auth etc.. classes all extending "user" just creates more overhead because in a proper system you'll have things from register, signup, login all cross referencing certain functions.
If you set it up properly ie;
$this->user->register();
$this->user->login();
$this->user->check_email();
or whatever.. you're putting everyting in the user class extending your main system core, this is what gives you the ability to add other things easily e.g.,
$this->log->insert('action','ip','date'); etc.
above your classes you can configure the autoload to do things automagically - or create an autoload function of only specifics, then each class in you're init() you'd put which extra classes you'd want to load ontop of it.
I wondering why this code is only finding one row in the accounts table, in the database, when there are two. When I var_dump the results it only has the data from the first row. What could be going on?
var_dump outputs this (some identifying details changed):PHP Code:class Database
{
private $dbHost = 'localhost';
private $dbUser = 'myusername';
private $dbPass = 'mypassword';
private $dbName = 'mydatabase';
private $dbConn = false;
public $result = array();
public function connect()
{
if (!$this->dbConn) $this->dbConn=mysql_connect($this->dbHost,$this->dbUser,$this->dbPass) or die(mysql_error());
}
public function setDB()
{
if ($this->dbConn) mysql_select_db($this->dbName) or die(mysql_error());
}
public function select($query)
{
$doQuery=@mysql_query($query) or die(mysql_error());
if ($doQuery)
{
$this->result = mysql_fetch_assoc($doQuery);
}
}
public function getResult()
{
return $this->result;
}
public function displayResults()
{
foreach ($this->result as $key => $value)
{
print $key.': '.$value.'<br />';
}
}
public function flushResult()
{
$this->result=array();
}
}
$accounts=new Database();
$accounts->connect();
$accounts->setDB();
$accounts->select("select * from accounts");
//$accounts->displayResults();
var_dump($accounts->getResult());
I probably did 100000000000 things wrong. Feel free to pick this code apart :PQuote:
array(11) { ["userID"]=> string(1) "1" ["username"]=> string(8) "sparkles" ["loginName"]=> string(16) "skittlesskittles" ["staffRanking"]=> string(1) "1" ["email"]=> string(20) "myemail@awebsite.com" ["password"]=> string(10) "mypassword" ["birthdate"]=> string(10) "0000-00-00" ["gender"]=> string(6) "female" ["activated"]=> string(3) "yes" ["activationCode"]=> string(10) "12345ABCDE" ["playedBefore"]=> string(3) "Yes" }
Well aside from the obvious - you shouldnt be using mysql extension.. at a minimum use mysqli (mysql improved) or PDO.
Make the adjustment here and it will work
On a side note.. if you want to print arrays nicely..PHP Code:if ($doQuery)
{
while($res = mysql_fetch_assoc($doQuery)) {
$this->result[] = mysql_fetch_assoc($doQuery);
}
}
PHP Code:echo "<pre>";
print_r($accounts->getResult());
echo "</pre>";
How does this part of the code work:
I'm assuming that for every row in the result set, this statement is somehow true, and then somehow when it gets to the end, it becomes false, but I do not know how.PHP Code:while($res = mysql_fetch_assoc($doQuery))
Edit: And wow the var dump output looks a lot better when doing it your way :o
Basically think of it as foreach ($result AS $i=>$v) .. while mysql_fetch_assoc($doQuery) returns something - it does what you want it to.. where as with mysqli_fetch_assoc it does what you originally intended (which is fetch the entire result set into an assoc[] array.Quote:
Originally Posted by evenstar7139
Yeah, with the <pre> tags it definately makes it nicer/easier to read - it's very handy when debugging and working with API's and things of the sort.
I always wondered how something like foreach() knows to move the row pointer down each time it loops. Do you know?
Nope.. I'm assuming it just counts how many keys are in it before hand, then runs through it. where as while() adds 1 at a time until it returns null... im assuming :P
What happened right here. I just saw this in a PDO tutorial and I'm not sure what's going on with the $STH variable:
The variable $STH was created in the first line of code I showed. It was apparently created by having $DBH's method prepare() shoved into it. How did $STH get access to the method execute()? I don't see this as having been placed in $STH.PHP Code:$STH = $DBH->prepare("INSERT INTO folks ( first_name ) values ( 'Cathy' )");
$STH->execute();
Thanks in advance.
It's to keep it OOP..
With a db class you can continously add more/remove variables and grab data and not have to rewrite things.
So if you wanted to do 2 queries in the same page with only 1 minor difference..
Its very simple here, but as you start using it more you'll see the benefits ;DPHP Code:$dbrun = $dbh->prepare('SELECT *
FROM tables
WHERE some_type < ? AND level = ?');
$dbrun->execute(array(2, 'admin'));
$result_set_one = $dbrun->fetchAll();
$dbrun->execute(array(1, 'user'));
$result_set_two = $dbrun->fetchAll();
Just to sort of help you get used to interpreting the manual...Quote:
Originally Posted by evenstar7139
Assuming $DBH is a PDO object, you'll see from the manual that PDO::prepare() returns a PDOStatement object (or false on failure). One of PDOStatment's methods is execute(), so that is now accessible from the $STH object.
However, more robust code would have first checked that $STH was not false -- unless they have enabled PDO::ERRMODE_EXCEPTION earlier in the code?
Yup, they had it on.Quote:
Originally Posted by NogDog
Yeah, I always have the manual open in a tab, as I refer to it frequently. Though, to be honest, sometimes I don't understand what it's saying. If I can't get answers from the manual, I see if Google can provide me with a plain-English explanation. Sometimes this works; sometimes it doesn't.Quote:
Originally Posted by NogDog
If all else fails, I post on a PHP forum (usually this one.) It's nice to have a source of guidance from real live people--gotten me out of so many frustrating situations over the years. I don't handle frustration the greatest. I probably would have given up were it not for people like you all. :)
Anyhoo, let's see if I get this.
PHP processed $DBH->prepare(), before it put it in $STH, so PDO::prepare() did not actually go in there, but rather its returned value did: PDO::execute(). Is this right?PHP Code:$STH = $DBH->prepare("INSERT INTO folks ( first_name ) values ( 'Cathy' )");
$STH->execute();
I would try playing with this in my code, if I were not having a little problem. I just noticed that after removing mysql_query and mysql_select_db from my script, it's not connecting to MySQL anymore. Here is the relevant part of my code:
I used the $connectString variable just so, upon receiving an error, I could output it to the screen and make sure that the values (like dbName) were actually getting used.PHP Code:private $dbHost = 'myhost'; //changed from what it really was
private $dbUser = 'myusername'; //changed from what it really was
private $dbPass = 'mypassword'; //changed from what it really was
private $dbName = 'mydatabase'; //changed from what it really was
private $DBH = false;
public $result = array();
public function connect()
{
try
{
if (!$this->DBH)
{
$connectString="mysql:host={$this->dbHost};dbname={$this->dbName}, {$this->dbUser}, {$this->dbPass}";
$this->DBH = new PDO($connectString);
$DBH->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
}
}
catch (PDOException $e)
{
print $connectString.'<br /><br />'.$e->getMessage();
}
}
When I visit the page in my browser I get (sensitive details changed):
I don't know how it can say it's not getting the username, or password, or anything. I see them right there in the string?Quote:
mysql:host=myhost;dbname=mydatabase, myusername, mypassword
SQLSTATE[28000] [1045] Access denied for user 'root'@'localhost' (using password: NO)012
Try that.PHP Code:$connectString="mysql:host={$this->dbHost};dbname={$this->dbName};";
$this->DBH = new PDO($connectString, $this->dbUser, $this->dbPass);
Okay, I changed the code, and the error I'm getting changed to this:
Quote:
Notice: Undefined variable: DBH in /pathtomyfile/Database.class.php on line 22 Fatal error: Call to a member function setAttribute() on a non-object in /pathtomyfile/Database.class.php on line 22
PHP Code:if (!$this->DBH)
{
$connectString="mysql:host={$this->dbHost};dbname={$this->dbName};";
$this->DBH = new PDO($connectString, $this->dbUser, $this->dbPass);
$DBH->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION ); //this is line 22
}
