(simple) return in if statement?

Code:

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        if(customer== ""){
                document.getElementById('customerInfo').innerHTML = "";
                return;
        }

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In this code, Why is the RETURN there? It doesn't work without the return, and it doesn't matter if i put return false, or return true.. (full code underneath)

Code:

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function toonKlant(klantnaam){
        if(klantnaam == ""){
                document.getElementById('hint').innerHTML = "";
                return;
        }
       
        if(window.XMLHttpRequest){
                xmlhttp = new XMLHttpRequest();
        } else {
                xmlhttp = new ActiveXObject('Microsoft.XMLHTTP');
        }
       
        xmlhttp.onreadystatechange = function(){
                if(xmlhttp.readyState == 4 && xmlhttp.status == 200){
                        document.getElementById("hint").innerHTML = xmlhttp.responseText;
                }
        }
        xmlhttp.open('GET','toonklant.php?name=', true);
        xmlhttp.send();
}

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Quote:

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Originally Posted by notflip

Code:

---

    if(customer== ""){
        document.getElementById('customerInfo').innerHTML = "";
        return;
    }

---

In this code, Why is the RETURN there? It doesn't work without the return, and it doesn't matter if i put return false, or return true

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It's just a cheap and unclear way of aborting the function if the required data hasn't been passed.

Having said that, this code seems to be making a request without appending the required data:

Quote:

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Code:

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    xmlhttp.open('GET','toonklant.php?name=', true);

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I copy pasted before the code was ready =) thanks for the response..

what would be a good way to abort the function if false? thanks!

Quote:

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Originally Posted by notflip

what would be a good way to abort the function if false? thanks!

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In this case, don't allow the function to be called without a parameter.