Failed to prepared the statement!

So I have a problem with prepare statement, at all everything works, but it won't work if I bind $table, any suggestions?

Quote:

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execSQL("SELECT id FROM ? WHERE id=?", array('si', $table, $u_id), style::Q_NUM_ROWS)

---

Code:

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const Q_GET_VALUE = 0;
const Q_NUM_ROWS = 1;
const Q_AFFECTED_ROWS = 2;

function user_exists($u_id, $table)
{
        if ( $this->execSQL("SELECT id FROM ? WHERE id=?", array('si', $table, $u_id), style::Q_NUM_ROWS) != 0 )
                return true;
               
        return false;
}
        function execSQL($sql, $params, $exec_type)
        {
                $stmt = $this->db_connect->prepare($sql) or die ("Failed to prepared the statement!");
       
                if ( !empty($params) )
                        call_user_func_array(array($stmt, 'bind_param'), $this->refValues($params));
   
                $stmt->execute();
           
                if ( $exec_type == self::Q_GET_VALUE )
                {
                        $parameters = array();
               
                        $meta = $stmt->result_metadata();
           
                        while ( $field = $meta->fetch_field() ) {
                                $parameters[] = &$row[$field->name];
                        } 
       
                        call_user_func_array(array($stmt, 'bind_result'), $this->refValues($parameters));
               
                        $stmt->fetch();
               
                        $result = $row;
                }
                else if( $exec_type == self::Q_NUM_ROWS)
                {
                        $stmt->store_result();
                        $result = $stmt->num_rows;
                }
                else
                {
                        $result = $stmt->affected_rows;
                }
           
                $stmt->close();

                return $result;
        }
function refValues($arr)
        {
                if (strnatcmp(phpversion(),'5.3') >= 0) //Reference is required for PHP 5.3+
                {
                        $refs = array();
                        foreach($arr as $key => $value)
                                $refs[$key] = &$arr[$key];
                               
                        return $refs;
                }
               
                return $arr;
        }

---

Not sure which DB extension you're using, but I know at least some do not allow bound parameters for table/column names, in which case you'd just have to embed that variable directly into the SQL string.

MySQL 5.5, table engine MylSAM, so what I suppose to do?

I think by engine he meant whether you're using mysqli, pdo, or something else all together. MySQLI and PDO do not support bound table/column names at all. See http://us3.php.net/manual/en/book.pdo.php#69304

Mysqli.
I'm know what you're saying, so what I suppose to do change 'FROM ?' to 'FROM $table' or how? :o

Yeah, you'll have to put the variable for the table name directly in the string:

PHP Code:

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"SELECT * FROM `$table` WHERE . . ." 


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We do something similar all the time at work with PDO using PostgreSQL, where the schema name is dynamic:

PHP Code:

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$sql = "SELECT * FROM {$this->dbSchema}.table_name . . ." 


---

execSQL("SELECT id FROM `$table` WHERE id=?", array('i', $u_id), style::Q_NUM_ROWS)
So it won't break something if i put a variable name in prepare statement?

Should be fine, with the exception that if the table name comes from user input or some other external source, then you'll need to sanitize it to make sure no SQL injection attacks/errors occur. With MySQLi, you can use the mysqli::real_escape_string() method.

Thank you for the answers.