Can anyone see the problems with this code as I just cant see it?

I wrote this code for a nav menu and I am getting some unexpected results. Here is the code.

PHP Code:

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<?php
// Script used to dynamically generate navigation manu for 

    $q = "SELECT link, name FROM top_menu";
    $r = mysqli_query($dbc, $q);

    $menu = mysqli_fetch_array($r, MYSQLI_ASSOC);

    
    
        echo '<nav>';
            echo '<ul id="menu">';
                echo '<li><a href="' . $menu[0]['link'] . '" title="' . $menu[0]['name'] . '">' . $menu[0]['name'] . '</a></li>'; // Home Link
                echo '<li><a href="' . $menu[1]['link'] . '" title="' . $menu[1]['name'] . '">' . $menu[1]['name'] . '</a>'; // Top Ten Travel List Link
                    echo '<ul id="first-sub-menu">';
                        $qs = "SELECT * FROM state_menu WHERE category_id=2";
                        $rs = mysqli_query($dbc, $qs);
                        while ($state_menu = mysqli_fetch_array($rs, MYSQLI_ASSOC)) {
                            
                            echo '<li><a href="'.$state_menu['link'].'" title="'.$state_menu['name'].'">'.$state_menu['name'].'</a></li>';
                            
                        }
                    echo '</ul>';
                echo '</li>';
                echo '<li><a href="'.$menu[2]['link'].'" title="'.$menu[2]['name'].'">'.$menu[2]['name'].'</a></li>'; // Travel Blog Link
                echo '<li><a href="'.$menu[3]['link'].'" title="'.$menu[3]['name'].'">'.$menu[3]['name'].'</a>'; // Resturant Menu
                    echo '<ul id="first-sub-menu">';
                        $qrs = "SELECT DISTICNT s.link, s.name, s.state_id FROM state_menu AS s LEFT JOIN resturant_menu AS r USING (state_id) WHERE r.state_id=s.state_id AND category_id=3 ORDER BY s.state_id";
                        $rrs = mysqli_query($dbc, $qrs);
                        while ($state_menu_rr = mysqli_fetch_array($rrs, MYSQLI_ASSOC)) {
                        
                            echo '<li><a href="'.$state_menu_rr['link'].'" title="'.$state_menu_rr['name'].'">'.$state_menu_rr.'</a>';
                                echo '<ul id="second-sub-menu">';
                        
                                    $qrm = "SELECT link, name FROM resturant_menu WHERE state_id={$state_menu_rr['state_id']}";
                                    $rr = mysqli_query($dbc, $qrm);
                                    while ($resturant_menu = mysqli_fetch_array($rr, MYSQLI_ASSOC)) {
                                    
                                        echo '<li><a href="rr.php'.$resturant_menu['link'].'" title="'.$resturant_menu['name'].'">'.$resturant_menu['name'].'</a></li>';
                                    }
                                echo '</ul>';
                            echo '</li>';
                        }
                    echo '</ul>';
                echo '</li>';
                echo '<li><a href="'.$menu[4]['link'].'" title="'.$menu[4]['name'].'">'.$menu[4]['name'].'</a>'; // Hotel Menu
                    echo '<ul id="first-sub-menu">';
                        $qhs = "SELECT DISTICNT s.link, s.name, s.state_id FROM state_menu AS s LEFT JOIN hotel_menu AS h USING (state_id) WHERE h.state_id=s.state_id AND category_id=4 ORDER BY s.state_id";
                        $hrs = mysqli_query($dbc, $qhs);
                        while ($state_menu_hr = mysqli_fetch_array($hrs, MYSQLI_ASSOC)) {
                        
                            echo '<li><a href="'.$state_menu_hr['link'].'" title="'.$state_menu_hr['name'].'">'.$state_menu_hr.'</a>';
                                echo '<ul id="second-sub-menu">';
                                
                                    $qhm = "SELECT link, name FROM hotel_menu WHERE state_id={$state_menu_hr['state_id']}";
                                    $hr = mysqli_query($dbc, $qhm);
                                    while ($hotel_menu = mysqli_fetch_array($hr, MYSQLI_ASSOC)) {
                                    
                                        echo '<li><a href="hr.php'.$hotel_menu['link'].'" title="'.$hotel_menu['name'].'">'.$hotel_menu['name'].'</a></li>';
                                    }
                                echo '</ul>'; // Closing the second-sub-menu.
                            echo '</li>';  // Closing the link from the state menu.
                        }
                    echo '</ul>';
                echo '</li>';
                echo '<li><a href="'.$menu[5]['link'].'" title="'.$menu[5]['name'].'">'.$menu[5]['name'].'</a></li>';
            echo '</ul>';
        echo '</nav>';

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Here is a screen shot of what I am getting:

Attachment 15367

From the way you are using $menu as a 2-D array, it appears to me that this...

PHP Code:

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    $menu = mysqli_fetch_array($r, MYSQLI_ASSOC); 


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...should instead be...

PHP Code:

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    $menu = mysqli_fetch_all($r, MYSQLI_ASSOC); 


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Unless I am missing something, why would you not put the first query result through a while loop as well?

PHP Code:

---

    
        echo '<nav>';
            echo '<ul id="menu">';
while ($menu = mysqli_fetch_array($r, MYSQLI_ASSOC)) {
                echo '<li><a href="' . $menu['link'] . '" title="' . $menu['name'] . '">' . $menu['name'] . '</a></li>';
.
.
.
} 


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I cant use a while statement for the first part because if I do it will repeat everything below it and there are other pages that need to be inserted under different links.