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Yeah it was quite awkward to figure out, there are still some minor issues but nothing stopping my emails working for the time being :)

Am i correct in saying that what you want to do is to show the user what value they selected in the drop down box after they submit the form?

To do this in html you would do something like


...

No problem :) If you do come up with a nice clean way around this or need anything else then post it up on here - I'm pretty sure this is a fairly common problem.

Yeah i know haha. But yeah function(xml) is only called once the ajax has finished however your GetNumbers() is the function you wish to return the array from (unless i am mistaken) and that has...

There are a few ways you could do it and mostly it will depend on the set up of the server you are running on.

file_get_contents() - Your hosting provider may not allow you to pull data from...

No worries mate, glad i could help :)

Ok the reason why it is not returning is because the function has actually finished running before the AJAX call is complete (or something to that effect).

You could set a interval (setInterval)...

You will probably want to change the format of you RecDate field, however try this



$date=date('Ymd',time()):
$result = mysql_query("SELECT * FROM vwsdata WHERE RecDate LIKE '".$date."%' ");

Ok what that sounds like is an error in your php that is causing the script to stop and therefore not processing that query and any following queries. Have you got errors turned on so you can see if...

Haha no response eh. Ok the problem you see above is basically because the SASL auxprop plugin requires the passwords in the database to be saved in plaintext. This is obviously not the best way to...

The answer to your question isn't as simple as it may first appear. If you are hosting a singular, low traffic website then i would say yes - try it yourself. The things you learn along the way will...

Also this is the last error produced:


Nov 10 17:24:31 ubuntu postfix/smtpd[1372]: warning: SASL authentication failure: incorrect digest response

Hey guys,

I have been in the process of setting up a mail server on ubuntu and have got everything working apart from the SMTP authentication to send mail out. The server is running postfix with a...

Honestly, i'm not entirely sure what you mean by this (my brain isnt working too fast today haha). Can you explain a little more?

Have you only tried it with google? That may simply be down to the fact that google doesnt want you to use its page on a remote sever?

I dont think this advice is 100% right.

A) Any host that allows you to use .htaccess will allow you to parse html as php.

B) The strain on the server is the same as simply processing a php...

Honestly i wouldnt worry too much about it. If you are creating a php page then it will be easier to stick with the .php file extension. This does tell malicious users that you are using php and it...

The problem is the fact that you have opening/closing php tags inside your php code. (before and after where you are starting your while loop).

Ok dont take this personally or anything, but i think you may be trying to run before you can walk. I have tidied up your script so it will at least run...but im not 100% sure what your trying to do....

function user_level_list($level) {
$query_sql="SELECT * FROM `training_auth_users` WHERE `user_level` = '".$level."'";
$query=mysql_query($query_sql);
$user_level = array();
...

You need to look into mysql_fetch_assoc or mysql_fetch_row. Every time these functions are run they retrieve the next row returned by your query.

In your case you look like you are only trying to...

Sorry for the slow reply, had a bit of a mad weekend xD Anyway, what you need to do...in an appropriate place in the script you put the previous code in...



$date=$_POST['date']; //or $_GET ...

Ok, heres the crack.

The first thing you need to do is find out how the data is being sent to your script.

At the top of the script put this line



print_r($_POST);

This line:


$query = "SELECT email FROM users WHERE email = '$check_email";


Change to

Ok thats a lot of code to look through so i'll have to look after work. However, the problem doesn't lie with your OOP skills I dont think.

Some things to help you narrow down your problem:
...