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$query = '/greatpeople/person/firstname[. = "$name"]'; (-> doesn't work)


$query = "/greatpeople/person/firstname[. = '$name']"; (-> works fine)


so it has to do with the quotation, don't...

Hi

Very usefulll example.

I am trying though to pass Alan as a variable from a form and doesnt work
you know why?

the variable works outside the query but not inside:

echo $name; ...