Type: Posts; User: waynesimmonds
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Apologies if i have posted this in the wrong place but i am kinda new to this forum.
I am running a captcha contact form, which has been running fine, however recently the captcha image...
In response to the coment made by theuedimaster
i modified the code in order to adopt your possible solution but stll had a parse error as follows.....
Parse error: parse error, expecting...
Yeh thats correct, i need the original filename of the image that is being uploaded with a counter variable being added onto the end of the filename not before as the post above your last states
Was wondering if you could help me?
I have been referring to your image upload article/tutorial.
This part of code is where you give the file a unique name before it is uploaded to...
After reading the article by member Bokeh on image uploading and creating some code i thought would work, im still stuck.
The code i have works to a certain point. I can...
im guessing that bit of code would come before the insert statment as this is generating the unused name.
The onto the insert statment i would have to relate to the $thisfile variable to get the...
Yeh thanks for that NightShift!
That worked fine, great stuff mate, thanks!
Wicked, Thanks for your help.
i shall get this sorted now and will post again if i get any probs.
I am trying to create an image upload that changes the name of the image i am uploading, from "example.jpg" to "photo1.jpg" so when i upload a new photo to the database it adds the id number...
I am trying to select certain records from a table where they match a certain date.
Within the table i have a field called datetime, which when a record is inserted into the database,...