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I believe that's more of a javascript question, which I am not very good at. Maybe put these images in divs with the link already there, have them hidden, and when the user presses the link show the...

IMO your best bet would be to initialize a link with every picture, just a small one at the bottom of it, then POST the data to the same page and have PHP handle it from there. Getting the current...

Have you echoed the POST data after you convert them with the strtotime() to see what they are, then compare them to the ones in the database manually ?

Or you both could quit your little cat fight and use HTML :-P



echo '<META HTTP-EQUIV="Refresh" Content="0; URL=http://www.myurl.com">';

I'm trying to overcome one feat, and I've just ran the course of my little knowledge of javascript. Here is the code that concerns us.



function loadXMLDoc()
{
if (window.XMLHttpRequest)
...

Yea lol, die() kind of kills the script bud. Glad it's working for ya.

Yea, when you use the $row['variable'] you have to make sure that the row your trying to catch matches it's name inside your...

Try


while($row = mysql_fetch_assoc($result))


instead of


while($row = mysql_fetch_array($result))

That's what we were looking for, the reason overall isn't show up in the table is because your using wrong variable id in your statements.

Remember this ?


while($row =...

I think I'm putting you through more trouble then I'm worth bud.

Put your code back in, and put a semicolon after the die() statment. It should read

die();

Then run the page and tell me...

Oh ! Put a ; after die()

it should be:

die();

Sorry about that.

Dont erase your code.

Ok, that might happen now because of the foreach we're using. Did you put the foreach before the while statment ? If so, copy & paste all of the code underneath die(); into a notepad, and put it back...

I edited the last post, did you do this:



$row=mysql_fetch_assoc($result);
foreach($row as $key=>$value){
echo $key . " = " . $value . "<br>";
}
die()

change


$row=mysql_fetch_array($result);
foreach($row as $value){
echo $row . " = " . $value . "<br>";
}
die();

put this right before your while statment, and copy and paste the results. This will klll your page the time being, but it will help us figure out whats going on.


...

Change:


while($row = mysql_fetch_array($result))
{

$id = $row[id];
$player = $row[player];
$ovr = $row[ovr];
$position = $row[position];

Is $ovr a link similar to your player-name ? Show me what you had that wasn't working. I dont see you attempting to echo $ovr anywhere on that page.

Show me the full code, and where $ovr is defined as something.

No problem at all.

Thats because I'm getting the contents of a text file. The obRequest.responseText is a name of a directory, I need that to be passed into
populateParentWindow(Directory), this is the problem.
...

Post the code of the $db class.

Not that I dont mind helping you out at all, but you should try experimenting around, these are pretty easy fixes. You are ware of the manual on PHP at PHP.net ? I've been leaving these little...

I'm guessing thats because the players name is seperated with a comma between last and first ? You could either remove the comma from the players name, or you could :



$char=array(" ", ",");...

Well Sessions are not my strong point, I've never got them to work the way I want to either unless I include() page after page. My solution has always been writing variables into a text file, and...

What code are you using to set your cookie ?

It should be something like this:



setcookie("MyCookieName","MyCookieVar",time()+3600,"/","yourdomain.com","0");


That sets a cookie for one...

Syntax was just a little off bud, that good ol' on the spot coding. Try this.



echo '<a href="2001' . $player_id . '-' . str_replace(' ','-',$player_name) . '.html">Player Name</a>';

...