look at this line
java.lang.NoSuchMethodError: org.springframework.core.io.ResourceEditor.<init>(Lorg/springframework/core/io/ResourceLoader;Lorg/springframework/core/env/PropertyResolver;)
I bet...
Unless craigslist admin offers an sdk to perform such tasks, it is not recommended to write or use any tools which can mimic web page activities. Your best bet would be to contact them and find out...
I would try the following
set the encoding before the execution of your code
e.g
<% request.setCharacterEncoding("utf-xx"); %>//replace xx that represents your language
<%@include...
u can use a hidden field and put the value in that and when you submit the form back to ur jsp, value will be in your jsp.
Or you can create a url and attach a parameter (name=value) that way you...
Here is the logic
In your jsp page when user submits the story, you save the time on the server side with the story, then when you print the results back, you have stimestamp for each story which...
problem has to be with the following part
if(data[m] != Math.min(data[m], data[m+1])
m+1 goes out of bounds. Look into it and make sure why you have to do m+1, if you must then you have check the...
if you remove the preceding 0x then
int dec = Integer.parseInt("1E",16);
will result in dec=30
You can use the above on a string of ex values dec value can be converted to char if needed
did u mean something like this?
int hex = 0x1E;
=30
?
or you have a string of characters which you want to convert to a hex string such as if I converted my first name Khalid to hex it would be ...
What is the exception?
For some basic java and mysql setup issues and there resolutions, please read the sticky it the top of this forum
Troubleshooting guide for some basic....
If you still haven't found solution, here are some suggesntions
First: are you in the same folder where your newly created class TwoArgsApp.class file is?
server side always executes first, if you are using Firefox go to C+Shift+J
this will bring up javascript error console, clear the console, then reload your page and see which error is being...
if I understand you correctly, you already are able to make changes to the div (ref. the relative content appears on right column) if so than most of your work as already done. At this point you...
you will have read the url on the second page, get the variable and then display, it won't automatically show up in the next page (this is presuming your AJAX code is actually sending request to this...
sounds like a path problem, this is how you can confirm e.g
http://stevenfoundling.com/images/Thumbnails/TP-2B.png
if I click on above image, you know which image should be displayed, so put this...