Type: Posts; User: jeffap
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so it is like when i have an image on the page it would be <img src="http://mydomain.com/images/1.jpg">?
right... i was thinking in a hard way... thanks anyway!
almost work out the whole thing...:(
ok i tested the above SQL and it does not work, the error message is as below:
Fatal error: Fatal error: Call to a member function bind_param() on a non-object in xxx.php on line 132
i think i...
thank you for your help eval
but now i am converting the obsolete mysql to mysqli (which is such a pain to me), so i guess the php code would be like?
I am making a simple filtering system for visitor that the criteria they choose is either in "column1" or "column2".
I had a thread regarding to sorting few days ago and I had been told that I can...
awesome NogDog :D
never know the "AS" can do the trick!
thanks a million!
i am using MYSQL and i would like to "SELECT' a table and sort according to a numerical value that i either get it from "column1" or "column2", so:
***if a number from column1 exist, then this...
awesome it works :D
thank you very much for your help!
the whole php and js code are pretty long so i will put what it is relevant
hi bionoid, your code is neat, clean and easy to understand, much better than mine :o
i have a question here, when you define var kw
var kw = String(str).split(','), i;
i want to validate an input value using the following function which included a regular expression. And my criteria of the value is:
1) any keyword with characters 'a-z', 'A-Z', '0-9', '-', '_',...
simple but great, i change it to if(!empty($newinput1)) anyway :D
i will use the FOR loop as there are many input:
please check the following code that i think it is relevant, please enlighten me :D
$result=mysql_fetch_array(mysql_query("SELECT * FROM db...
i trim $newinput1 but not $originalinput1. $originalinput1 is retrieved from db using SELECT field1 FROM db bla bla bla...
is it because it can be used only on SELECT so i can't use...
Hi I have problems creating mysql statement.
I want to update field1 in table db only if variable $newinput1 is not empty, otherwise field1 will use the original value $originalinput1.
I do not...
<input type=hidden name="someName" value="">
is it because you did not add double quotation between - hidden -????
Otherwise, just suggesting, may be you can add css like: display:none; ???
i just took some elementary javacript class so i thought this must have violated some basic principle *blush*
anyway i will put the code here for easier reading:
sorry i have a stupid question
i have made some functions to control the class of some divs, and i m using a lot of document.getElementById('divname').style.
my functions work pretty well, but...
so simple to have it solved *banghead*
i have built a username check on a textfield that when the username already existed in the database there will be an alert
everything works okay...
Thank you for your help Nep0leon
I am actually using more or less the same script as yours to add numerous options as well as having the array defined var list= ["area1", "area2" bla bla bla]
Oh no... :(