how to upload image files and doc files into the sql server database through asp..
i m new to dis..i need a complete code dat how u can upload doc files and image files into da sql database in asp using dreamweaver..
i think u need a component dat uploads files..i downloaded two components..
viz, aspsmart upload and aspupload
now i need a code dat uploads da files into da database..
thanx in advance...
He is talking about the fact that you cannot upload a file to a database. You have the code to upload the file to your server, aspupload, so just use that.
--Ubik
If I have no idea what you are talking about, then I will pretend I know and answer accordingly.
like a user will browse through his computer, select da file and den hit da upload button....
da respective image or doc file will be den saved into da table of sql server database..!
Class FileUploader
Public Files
Private mcolFormElem
Private Sub Class_Initialize()
Set Files = Server.CreateObject("Scripting.Dictionary")
Set mcolFormElem = Server.CreateObject("Scripting.Dictionary")
End Sub
Private Sub Class_Terminate()
If IsObject(Files) Then
Files.RemoveAll()
Set Files = Nothing
End If
If IsObject(mcolFormElem) Then
mcolFormElem.RemoveAll()
Set mcolFormElem = Nothing
End If
End Sub
Public Property Get Form(sIndex)
Form = ""
If mcolFormElem.Exists(LCase(sIndex)) Then Form = mcolFormElem.Item(LCase(sIndex))
End Property
Public Default Sub Upload()
Dim biData, sInputName
Dim nPosBegin, nPosEnd, nPos, vDataBounds, nDataBoundPos
Dim nPosFile, nPosBound
If oUploadFile.FileSize > 0 Then Files.Add LCase(sInputName), oUploadFile
Else
nPos = InstrB(nPos, biData, CByteString(Chr(13)))
nPosBegin = nPos + 4
nPosEnd = InstrB(nPosBegin, biData, vDataBounds) - 2
If Not mcolFormElem.Exists(LCase(sInputName)) Then mcolFormElem.Add LCase(sInputName), CWideString(MidB(biData, nPosBegin, nPosEnd-nPosBegin))
End If
nDataBoundPos = InstrB(nDataBoundPos + LenB(vDataBounds), biData, vDataBounds)
Loop
End Sub
'String to byte string conversion
Private Function CByteString(sString)
Dim nIndex
For nIndex = 1 to Len(sString)
CByteString = CByteString & ChrB(AscB(Mid(sString,nIndex,1)))
Next
End Function
'Byte string to string conversion
Private Function CWideString(bsString)
Dim nIndex
CWideString =""
For nIndex = 1 to LenB(bsString)
CWideString = CWideString & Chr(AscB(MidB(bsString,nIndex,1)))
Next
End Function
End Class
Class UploadedFile
Public ContentType
Public FileName
Public FileData
Public Property Get FileSize()
FileSize = LenB(FileData)
End Property
Public Sub SaveToDisk(sPath)
Dim oFS, oFile
Dim nIndex
If sPath = "" Or FileName = "" Then Exit Sub
If Mid(sPath, Len(sPath)) <> "\" Then sPath = sPath & "\"
Set oFS = Server.CreateObject("Scripting.FileSystemObject")
If Not oFS.FolderExists(sPath) Then Exit Sub
Set oFile = oFS.CreateTextFile(sPath & FileName, True)
For nIndex = 1 to LenB(FileData)
oFile.Write Chr(AscB(MidB(FileData,nIndex,1)))
Next
oFile.Close
End Sub
Public Sub SaveToDatabase(ByRef oField)
If LenB(FileData) = 0 Then Exit Sub
If IsObject(oField) Then
oField.AppendChunk FileData
End If
End Sub
'NOTE - YOU MUST HAVE VBSCRIPT v5.0 INSTALLED ON YOUR WEB SERVER
' FOR THIS LIBRARY TO FUNCTION CORRECTLY. YOU CAN OBTAIN IT
' FREE FROM MICROSOFT WHEN YOU INSTALL INTERNET EXPLORER 5.0
' OR LATER.
' Create the FileUploader
Dim Uploader, File
Set Uploader = New FileUploader
' This starts the upload process
Uploader.Upload()
'******************************************
' Use [FileUploader object].Form to access
' additional form variables submitted with
' the file upload(s). (used below)
'******************************************
Response.Write "<b>Thank you for your upload " & Uploader.Form("fullname") & "</b><br>"
' Check if any files were uploaded
If Uploader.Files.Count = 0 Then
Response.Write "File(s) not uploaded."
Else
' Loop through the uploaded files
For Each File In Uploader.Files.Items
' Check where the user wants to save the file
If Uploader.Form("saveto") = "disk" Then
' Save the file
File.SaveToDisk "E:\UploadedFiles\"
ElseIf Uploader.Form("saveto") = "database" Then
' Open the table you are saving the file to
Set RS = Server.CreateObject("ADODB.Recordset")
RS.Open "MyUploadTable", "CONNECT STRING OR ADO.Connection", 2, 2
RS.AddNew ' create a new record
' Open the table you are saving the file to
Set RS = Server.CreateObject("ADODB.Recordset")
RS.Open "MyUploadTable", "CONNECT STRING OR ADO.Connection", 2, 2
RS.AddNew ' create a new record
Where did you find this code at? I was able to upload to a folder, but I do not know the table data-types for uploading to the database so I get an error when trying to upload.
Last edited by chrismartz; 04-22-2006 at 10:22 AM.
I got this to work. Although I only have images being able to be saved and then be pulled back to a page. The table should be set up like this (in MSSQL 2000 or 2005):
filename--------text
filesize---------char
contenttype----text
filedata---------image
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