$query = "SELECT kunde,projektnr from emp_kunde";
$result = mysql_query($query) or die("Query failed: $query");
$projekt = array();
while ($row = mysql_fetch_assoc($result))
{
array_push($projekt, $row["projektnr"]);
}
$hprojekt = array_unique($projekt);
<td align="center">
<select name="projekt">
<? foreach($hprojekt as $value) { ?>
<option value="<?= $value ?>"><?= $value ?></option>
<? } ?>
</select>
</td>
<?= $line["projekt"] ?>//this is for printing
let say the value for project combo box is
Apple,Mango so when i select mango from project field and then submit the form i will get mango as printed value,i want mango must be shown selected in new line,whatever i select it will be shown as selectd on next new line,but in my case always Apple as selected in new line
let say in my list
1.Dad
2.Mom
3.Didi //if i select didi from this field then new line should be didi
4.Uncle as selected
5.Aunty
<?PHP
foreach($hprojekt as $value) {
if ($value == "Uncle") { #set Uncle to the value that you want selected.
echo "<option value=\"$value\" selected=\"selected\">$value</option>";
}
else {
echo "<option value=\"$value\">$value</option>";
}
}
?>
<? foreach($hprojekt as $value) { ?>
<option value="<?= $value ?>" <? if ($HTTP_POST_VARS['projekt'] == $value){ echo "SELECTED";}?>><?= $value ?></option>
<? } ?>
project_00 //default selected value
project_01
project_02
project_03
when i choose project_02 and subit the form then im getting project_02 as selected
this works fine but when i login for next time im getting project_00 as default is it possible to get slected one as default one ,when login for next time
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