if( odd or even number)

[copes]

Hello,

im having a real headache about how to write a if statement which basically says

if($number is odd) { do this } else { do this }

i dont think of a mathical way of determening if a number is even or odd, but then again im not very good at maths, there probably is.

the numbers will only go up to about 40, if there is some way of maybe doing it by saying

if($number = 2,4,6,8,10,12,14 etc) {} else {}

but that doesnt work i don't think

Is there an easy way to do this if?

[Webnerd]

$number % 2 ==0

Will return even numbers. Basically it states:

If the remainder of your number divided by two is zero

[TecBrat]

$number % 2 ==0

Will return even numbers. Basically it states:

If the remainder of your number divided by two is zero

You beat me to it, but here's a real world example stripped out to be generic:

<?
if ($id % 2){    //  **   even is zero, or boolean false.
     $var="odd";  //  **   so this TRUE action is for odds
   } else {
     $var="even"; //  **   this else action is for evens.
   }
?>

[pcthug]

For future reference, this is the PHP Modulus Arithmetic Operator.