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Thread: Function Array of Names

  1. #1
    Join Date
    Nov 2006
    Location
    Springfield, MO
    Posts
    1,541

    Function Array of Names

    If I had the following code:

    Code:
    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
    "http://www.w3.org/TR/html4/loose.dtd">
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
    <title>4.9</title>
    </head>
    
    <body>
    <script type="text/javascript">
    function e_names(my_names){
    //create array list of names, return number of names in array than end in either
    //ie or y
    
    var my_array_names=new Array("Ryan Butler", "Pat Lonie", "Michell Lay");
    }
    
    </script>
    
    </body>
    </html>
    I'm trying to find a way to call and check to see whether the array of names contains an "ie" or "y" which it will since I created my array to have those. I'm guessing that maybe I'll be using argument.length to check the number?? I'm thinking it needs to be a regular expression to check which ones end in "ie" or "y."

    If anyone could shed some light somewhere it would be great.
    Ryan Butler

    Ryan Butler.org

  2. #2
    Join Date
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    Location
    Ontario Canada
    Posts
    1,160
    Loop through the array and then check each entry using a regular expression.

    Drew

  3. #3
    Join Date
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    Location
    Springfield, MO
    Posts
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    So something like this?


    Code:
    <html>
    <head>
    
    </head>
    <body>
    function e_names(my_names){
    //create array list of names, return number of names in array than end in either
    //ie or y
    
    //create an empty variable to determine how many names end in requirements
    var count=[];
    
    //create a for loop to loop through my array set
    for(var i=0; i < my_array.length; i ++){
        if(count[my_array[i]]){
          count[my_array[i]]+=1;
        }
      }
    }
    
    </script>
    
    <script type="text/javascript">
    
    //create new array variable to hold various values to test for
    var my_array = new Array("Butler", "Lonie", "Lay");
    //create result variable and set equal to my function call and pass parameter
    var result=e_names(my_array);
    
    //display the message in the browser
    document.writeln("The number of names that end in either ie or y are " + result);
    </script>
    </body>
    </html>
    Except perhaps replacing count with a regular expression?
    Ryan Butler

    Ryan Butler.org

  4. #4
    Join Date
    Oct 2006
    Location
    Ontario Canada
    Posts
    1,160
    Kind of.
    Here is a sample:
    Code:
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
    <title>Untitled Document</title>
    <script>
    
    var NameArray =new Array("Ryan Butler", "Pat Lonie", "Michell Lay");
    
    
    for (var i in NameArray)
    {
    	var name = NameArray[i];
    	if (name.search(/ie/) != -1)
    	{
    		alert(name +  " contains ie")
    	}
    	if (name.search(/y/) != -1)
    	{
    		alert(name +  " has a y")
    	}
    }
    
    
    </script>
    </head>
    
    <body>
    </body>
    </html>
    Drew

  5. #5
    Join Date
    Aug 2007
    Posts
    3,767
    Or using for loops and ignoring case:
    PHP Code:
    var NameArray = ["Ryan Butler""Pat Lonie""Michell Lay"];
    for (var 
    NameArray.length-1>= 0i--) {
       var 
    name NameArray[i];
       if (/
    ie/i.test(name)) {
          
    alert(name " contains ie");
       }
       if (/
    y/.test(name)) {
          
    alert(name " contains y");
       }

    OR for multiple ones:
    PHP Code:
    var NameArray = ["Ryan Butler""Pat Lonie""Michell Lay"];
    var 
    checks = [/ie/i,/y/i];
    for (var 
    NameArray.length-1>= 0i--) {
       var 
    name NameArray[i];
       for (var 
    checks.length-1>= 0j--) {
       if (
    checks[i].test(name)) {
          
    alert(name " contains "+checks[i].replace(/\//g,"");
       
    }
      }


  6. #6
    Join Date
    Aug 2007
    Posts
    3,767
    Edit has expired on the previous post, so I better so what I meant. There is a back slash missing:
    PHP Code:
    alert(name " contains "+checks[i].replace(/BACKSLASH//g,""); 

  7. #7
    Join Date
    Nov 2006
    Location
    Springfield, MO
    Posts
    1,541
    Thanks everyone. I was able to adjust my script to return a value after about an hour of work. I'm reminding myself how pesky JS can be.
    Ryan Butler

    Ryan Butler.org

  8. #8
    Join Date
    Nov 2013
    Posts
    1

    following code lets u enter the names into an array and then check what it ends with

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
    <title>Untitled Document</title>
    <script>

    var NameArray =new Array("Ryan Butler", "Pat Lonie", "Michell Lay");
    var new_name,index,last;

    while (new_name= prompt("pls type a new name"," "))
    {
    last= NameArray.length-1;
    while(last>=0&&NameArray[last]>new_name)
    {
    NameArray[last+1]=NameArray[last];
    last--;
    }
    NameArray[last+1]=new_name;
    document.write("<p><b>the new name list is:<b>","<br />");
    for (index=0;index<NameArray.length;index++)
    document.write(NameArray[index], "<br />");
    document.write("<p>");
    }

    for (var i in NameArray)
    {
    var name = NameArray[i];
    if (name.search(/ie/) != -1)
    {
    alert(name + " contains ie")
    }
    if (name.search(/y/) != -1)
    {
    alert(name + " has a y")
    }
    }


    </script>
    </head>

    <body>
    </body>
    </html>

  9. #9
    Join Date
    Oct 2006
    Location
    Ontario Canada
    Posts
    1,160

    already answered - 5 years ago

    Reshmee -> The tread was answered back in 2008....... 5 years ago.

  10. #10
    Join Date
    Mar 2007
    Location
    localhost
    Posts
    2,318
    Well for what its worth, this is how I did it.

    HTML Code:
    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
    "http://www.w3.org/TR/html4/loose.dtd">
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
    <title>4.9</title>
    </head>
    
    <body>
    <script type="text/javascript">
    //create array list of names, return number of names in array than end in either
    //ie or y
    var my_array_names=new Array("Ryan Butler", "Pat Lonie", "Michell Lay");
    var count = 0;
    while(my_array_names.length){
    	var tmp = my_array_names.shift();
    	tmp = tmp.toLowerCase().slice(-2);
    	if( tmp=="ie" || tmp.slice(-1)=="y" ) count++;
    }
    console.log("You have an array with : "+ count +" names that either have 'ie' or a 'y' at the end.")
    
    
    
    </script>
    
    </body>
    </html>
    You can replace the console.log for an alert if you prefer. Don't see why you needed a function with the array in it so I got rid.
    Yes, I know I'm about as subtle as being hit by a bus..(\\.\ Aug08)
    Yep... I say it like I see it, even if it is like a baseball bat in the nutz... (\\.\ Aug08)
    I want to leave this world the same way I came into it, Screaming, Incontinent & No memory!
    I laughed that hard I burst my colostomy bag... (\\.\ May03)
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