Trim string length if above certain length

[Shaolin]

Hi Guys

I have a string. If it is longer than 25 chars I want to delete the excess chars. How can I do this?

[Shaolin]

I have written some code but it doesnt work when I try to empty the charAt value.

var all = "1234567890123456789012345678901234567890";
for(var k=0;k<all.length;k++) {
	if(k>25) {
		all.charAt(k) = ""; //This doesnt work
	}
}

[Declan1991]

str = str.substring(0,25);

EDIT: Or in your style

var all = "1234567890123456789012345678901234567890";
all = all.substring(0,25);

As a general rule, try to keep things simple. JavaScript can work out whether the string is too long, you don't have to worry about it.

[Shaolin]

Thanks. That was really simple in comparsion to what I was doing! I have another problem, at the end of some of my words I have a comma. How do I check for and delete it? Note that there will be commas in other parts of the sentence but the one I want to delete is the one that comes at the end of the word.

[Declan1991]

I'm not sure exactly what you mean. "hello, hello, hello," should one or three commas be deleted. I'll presume it's three, and this is what you'd use

var all = "1234567890123456789012345678901234567890";
all = all.substring(0,25).replace(/(\w)\,/g,"$1");

[Dok]

Wouldn't

all = all.substring(0,25).replace(/(\w)\,/g,"$1");

be the same as

all = all.substring(0,25).replace(/,/g, '');

?

(BTW: Comma is not a special char so it shouldn't be escaped)

[Declan1991]

Comma doesn't have to be escaped, but I prefer to escape all punctuation, it still works.

replace(/(\w)\,/g,"$1");
replaces a comma if it's at the end of a word, while the other replaces all commas regardless of where they are. I'm not a hundred percent sure what the person wants, but looking at it again, this is probably what they want.

all = all.replace(/(\w)\,/g,"$1").substring(0,25);