Just pass in the userid when you call the function. For example:
PHP Code:
function saveItem($userid) {
echo "User ID: $userid";
}
$userid = 66;
saveItem($userid);
This may also help, especially the part about parameters.
Thank's for your helpful response, I've tried placing the $userid variable in a function and calling it but the value that is sent is still null.
If on the other hand I specify a value above the function call like in your example:
$userid = 66;
saveItem($userid);
Then the value 66 is inserted in the database.
But the value that I am trying to insert isn't a specific value like 66, rather it has been taken from the database and stored in a variable ($userid).
Is it possible for you to show me what the code would look like, based on my code for inserting value from the variable $userid in to the database?
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