Increment a variable in preg_replace()?

[weenis]

Is there any way I can increment a variable for each replacement in a preg_replace() statement?

So basically if I have something like:

<cut>Text one</cut>
<cut>Text two</cut>

And after preg_replace() I would like to get:

<div id="cut_1">Text one</div>
<div id="cut_2">Text two</div>

with that incrementing "cut_1" and "cut_2" part.

[weenis]

I should mention I have tried things like:

preg_replace("/<cut>(.*)</cut>/i", "<div id=\"cut_".++$x."\">$1</div>", $inputText);

But that doesn't work because the ++$x is just evaluated when preg_replace() is initially called.

[NogDog]

You could use preg_replace_callback() with a callback function that will do the incrementing via a static variable in the function.

[weenis]

Looks like that's exactly what I need. Thanks!