[RESOLVED] randomArray with exceptions

[simpleAnswers]

I need a some help with some code I've assembled from different websites.
I want to create an array of 3 random numbers between lets say 1 & 10 but with the exception or the exclusion of lets say 6.
My limited knowledge of functions, their parameters and loops prevent me for coming up with a solution, any advice would be greatly appreciated. Here's what I've got so far:

var myNumArray = create_unique_random_array(3,10,5);

function create_unique_random_array(num_elements,max,current_pic) {

    var temp, nums = new Array;
	
    for (var element=0; element<num_elements; element++) {

        //IMPORTANT: DON'T FORGET THE SEMI-COLON AT THE END
        while((temp=number_found(randomizeMe(this,{maxNumber:max, exempt:current_pic),nums))==-1);
		
		
        nums[element] = temp;
    }

    return (nums);
}

function number_found (random,number_array) {
	
    for (var element=0; element<number_array.length; element++) {

        if (random==number_array[element] ) {
            return (-1);
	}
   }

    return (random);
}

function randomizeMe(me, options){
    var options = options || {}; // setup the options
    var imExempt = options.exempt || null; // capture the exempt numbers
    var maxNum = options.maxNumber || 0; // capture the maximum number to randomize	
    var rand_no = Math.floor(Math.random()*maxNum); // run the random numbers
    
    if(imExempt != null){ // check to see if there are any exempt numbers
        imExempt = imExempt.toString(); // turn the exemptions into a string
        for(i=0; i <= maxNum; i++){ // loop throught the set number
            if(imExempt.search(rand_no) != -1){ // check for exemptnumbers			
                return randomizeMe(me, {exempt: imExempt, maxNumber:maxNum}); // start over 
            }
        }
    }    
    return rand_no;// return the new random number
} 

document.write(myNumArray);