# Thread: [RESOLVED] randomArray with exceptions

1. Registered User
Join Date
Oct 2009
Posts
9

## [RESOLVED] randomArray with exceptions

I need a some help with some code I've assembled from different websites.
I want to create an array of 3 random numbers between lets say 1 & 10 but with the exception or the exclusion of lets say 6.
My limited knowledge of functions, their parameters and loops prevent me for coming up with a solution, any advice would be greatly appreciated. Here's what I've got so far:
Code:
```var myNumArray = create_unique_random_array(3,10,5);

function create_unique_random_array(num_elements,max,current_pic) {

var temp, nums = new Array;

for (var element=0; element<num_elements; element++) {

//IMPORTANT: DON'T FORGET THE SEMI-COLON AT THE END
while((temp=number_found(randomizeMe(this,{maxNumber:max, exempt:current_pic),nums))==-1);

nums[element] = temp;
}

return (nums);
}

function number_found (random,number_array) {

for (var element=0; element<number_array.length; element++) {

if (random==number_array[element] ) {
return (-1);
}
}

return (random);
}

function randomizeMe(me, options){
var options = options || {}; // setup the options
var imExempt = options.exempt || null; // capture the exempt numbers
var maxNum = options.maxNumber || 0; // capture the maximum number to randomize
var rand_no = Math.floor(Math.random()*maxNum); // run the random numbers

if(imExempt != null){ // check to see if there are any exempt numbers
imExempt = imExempt.toString(); // turn the exemptions into a string
for(i=0; i <= maxNum; i++){ // loop throught the set number
if(imExempt.search(rand_no) != -1){ // check for exempt numbers
return randomizeMe(me, {exempt: imExempt, maxNumber: maxNum}); // start over
}
}
}
return rand_no;// return the new random number
}

document.write(myNumArray);```
Last edited by Kor; 10-28-2009 at 08:37 AM. Reason: wrap the code [code][/code]