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Plese Help me.....
<coad>
<script language="javascript">
function show(check){
if(document.getElementById(check).style.display=='none'){
document.getElementById(check).style.display='block';
}
else {
document.getElementById(check).style.display='none';
}
}
</script>
<table width="100%">
<tr><td>
<?php $res=mysql_query("select * from new_price where make='$make'");
while($row=mysql_fetch_array($res)){
$sr=$row['sr'];
$name=$row['name'];
$img=$row['img'];
?>
<table cellpadding="0" class="ov" cellspacing="0" width="100%" style="background-color:#676C98; font-weight:bold;">
<tr><td height="20" width="70%">
<a onclick="show('<?php echo $sr; ?>');"style=" cursor ointer; text-decoration:none; padding-left:10px;"><?php
echo $name; ?></a></td>
<td align="center"><?php echo $price; ?></td>
</tr></table>
</td></tr>
<tr style="display:none" bgcolor="#AAADCC" id="<?php echo $sr; ?>" align="center">
<td>
<img src="admin/upload/<?php echo $img; ?>" style="width:350px; height:280px"/></td></tr>
<?php } ?>
</table>
</coad>
Qus: onclick show one div hide other div in loop
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