Javascript Require File To Run

[simonstaton]

Hi,

Is it possible to make a .js file only run if another .js file is located.

so lets say I have:

                                Index.html
                                       |
                                       |
                     -----------------
                    |
                    |
                Scripts.js
                     |
              ------
             |
        Required.js

in the Index it will call to Scripts.js but then scripts.js will only run if Required.js is in the same directory.

Simon

[aj_nsc]

Well, there are no include or require statements in JS, so the only way you can do it is to put both script tags in index.html.

However, you have an ability to check then. In scripts.js you would use this:

if(typeof yourFunctionName == 'function') { 
   //the rest of your code
}

Replace yourFunctionName in the above statement with a function name that is found in Required.js. If Required.js has been loaded, then typeof will return 'function' - voila - a way to 'require' javascript.

[simonstaton]

Nice!! thanks aj will give that one a go

[simonstaton]

Ok got it now, Solved

[Champloo11]

Well, there are no include or require statements in JS, so the only way you can do it is to put both script tags in index.html.

However, you have an ability to check then. In scripts.js you would use this:

if(typeof yourFunctionName == 'function') { 
   //the rest of your code
}

Replace yourFunctionName in the above statement with a function name that is found in Required.js. If Required.js has been loaded, then typeof will return 'function' - voila - a way to 'require' javascript.

Not Natively, however there is a site made for converting PHP functions into javascript functions. http://phpjs.org/functions/include:433 , the function uses an ajax call to retrieve a files contents.