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Thread: getElementsByTagName('TagName').length is not working in FireFox

  1. #1
    Join Date
    Nov 2009
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    11

    getElementsByTagName('TagName').length is not working in FireFox

    Hi,

    xmlDoc.getElementsByTagName('TagName').length is not working in FireFox
    xmlDoc.getElementsByTagName('TagName').length is returning 0 in FireFox.
    its worth mentioning taht xmlDoc.load(XmlFile) is working fine in Firefox
    while its ok in IE. Any fix for this?
    following is my code:
    Thanks

    if (mozilla) {
    xmlDoc = document.implementation.createDocument("", "", null);
    xmlDoc.async=false;
    xmlDoc.load(XmlFil);
    }
    else if (ie)
    {
    xmlDoc = new ActiveXObject("MSXML2.DOMDocument");
    xmlDoc.async = false;
    while(xmlDoc.readyState != 4) {};
    xmlDoc.loadXML(XmlFil);
    }

    var noOfBooks = xmlDoc.getElementsByTagName('Book').length;



    <Books>
    <Book></Book>
    <Book></Book>
    <Book></Book>
    </Books>

  2. #2
    Join Date
    Dec 2005
    Posts
    2,984
    I may be mistaken, but I believe you need to get the root element first, and perform all DOM requests/manipulations from that root object. In this case:

    Code:
    xmlDoc.documentElement.getElementsByTagName('Book');
    I've switched careers...
    I'm NO LONGER a scientist,
    but now a web developer...
    awesome.

  3. #3
    Join Date
    Nov 2009
    Posts
    11
    Thanks for reply aj_nsc,

    that doesnt work "xmlDoc.documentElement.getElementsByTagName('Book').length;", code breakes at this line.

  4. #4
    Join Date
    Dec 2005
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    Works fine for me.

    Are you sure XmlFil points to the proper Xml File?

    My (working) code in FF:
    Code:
    XmlFil = "test.xml";
    xmlDoc = document.implementation.createDocument("", "", null);
    xmlDoc.async=false;
    xmlDoc.load(XmlFil);
    alert(xmlDoc.documentElement.getElementsByTagName('Book').length);
    and the xml file:
    Code:
    <Books>
    <Book></Book>
    <Book></Book>
    <Book></Book>
    </Books>
    For the record, it appears you don't even need the documentElement part.
    Last edited by aj_nsc; 05-27-2010 at 07:14 AM.
    I've switched careers...
    I'm NO LONGER a scientist,
    but now a web developer...
    awesome.

  5. #5
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    Nov 2009
    Posts
    11
    well, actually i am not picking an xml file here, 'xmlFile' is basically just a a string "xmlDoc.load(xmlFile)",

  6. #6
    Join Date
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    Posts
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    Code:
    	var strXML = "<Books><Book></Book><Book></Book><Book></Book></Books>";
    	if(mozilla) {
    		//mozilla
                    xmlParser = new DOMParser();
                    xmlDocum = xmlParser.parseFromString( strXML, 'text/xml');
                    xmlSerializer = new XMLSerializer();
    	} else {
    		//ie
    		xmlDocum = new ActiveXObject("Microsoft.XMLDOM");
                    xmlDocum.async=false;
                    xmlDocum.loadXML( strXML);
    	}
    	
    	alert(xmlDocum.getElementsByTagName('Book').length);

    Works like a charm. Comes from:
    http://www.discussweb.com/html-css-j...-into-xml.html

    EDIT: I have no idea why the xmlSerializer was included in the above example. Removing it will have no negative consequences.
    Last edited by aj_nsc; 05-27-2010 at 08:21 AM.
    I've switched careers...
    I'm NO LONGER a scientist,
    but now a web developer...
    awesome.

  7. #7
    Join Date
    Nov 2009
    Posts
    11
    Thanks aj, i will try it right now, will let you know if it works.

  8. #8
    Join Date
    Nov 2009
    Posts
    11
    thanks aj, its working, just one last bit, the following code is not returning node value:
    xmlDoc.getElementsByTagName("Book")[i].nodeValue;

    returns null,

    i also treid xmlDoc.getElementsByTagName("Book")[0].text, returns undentified object,
    Last edited by Alisyed; 05-27-2010 at 09:00 AM.

  9. #9
    Join Date
    Dec 2005
    Posts
    2,984
    That's because the node itself doesn't have a value, it has a child element which is text. The child element has a value, however. So, do this:

    Code:
    xmlDoc.getElementsByTagName("sortcode")[i].firstChild.nodeValue
    I've switched careers...
    I'm NO LONGER a scientist,
    but now a web developer...
    awesome.

  10. #10
    Join Date
    Nov 2009
    Posts
    11
    thaks a lot for your help aj, it works now
    cheers
    Last edited by Alisyed; 05-27-2010 at 09:18 AM.

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