[RESOLVED] Timing Delema

[ZZY]

I have a script that fades a picture in and i want it to disappear when a certain function runs.. i tried using an if/else (when i == 2) and defining the variable in the first function but return; stops the code, any other ideas?

[Jona]

Hi,

Could you please post the code or (preferably) a link? It's a little hard to help out when there's nothing to work with. ;-)

[ZZY]

i is defined here in a loop (function that calls the first function at the end for infinite loop) and note this is only one of many identical functions that only change the opacity.

function pic1h(){
i = 2;
// return i; only reason i dont put it in is because it stops timeout from calling the next function
document.myimg.style.opacity = 1/10;
document.myimg.style.filter = 'alpha(opacity=' + 1*10 + ')';
setTimeout('pic1i ()', 100);
}

And here is the function that is calling i to tell the picture to fade out.
The beggining of this code is executed onclick

function box1end(i){
if (i == 2)
  {
document.myimg4.style.opacity = 0/10;
document.myimg4.style.filter = 'alpha(opacity=' + 0*10 + ')';
document.getElementById('gal4').style.opacity = 0/10;
document.getElementById('gal4').style.filter = 'alpha(opacity=' + 0*10 + ')';
document.getElementById('gal5').style.opacity = 0/10;
document.getElementById('gal5').style.filter = 'alpha(opacity=' + 0*10 + ')';
document.getElementById('gal6').style.opacity = 0/10;
document.getElementById('gal6').style.filter = 'alpha(opacity=' + 0*10 + ')';
  }
else
  {
  document.myimg4.style.opacity = 10/10;
  document.myimg4.style.filter = 'alpha(opacity=' + 10*10 + ')';
  setTimeout('box1end()', 100);
  }
}

[Jona]

I might be missing something, but... why not just move your return statement to the end of the function?

function pic1h(){
i = 2;
document.myimg.style.opacity = 1/10;
document.myimg.style.filter = 'alpha(opacity=' + 1*10 + ')';
setTimeout('pic1i ()', 100);
 return i;
}

[ZZY]

i didnt think you could execute anything after settimeout, thanks