PHP Link code

[stepbystep]

hye..

i am facing some problem in showing the link in my page. I try to alter but there are still error. So, i would like if someone can please help detect the error. Thanks in advance.

here are my code:

<?php
$q=$_GET["q"];

include("connection.php");

$sql="SELECT * FROM menu WHERE Category = '".$q."'";

$result = mysql_query($sql);

echo "<table border='1'>
<tr>
<th>    Menu    </th>
<th>    Image    </th>
<th>    Descriptions    </th>
<th>    Price (RM)    </th>
</tr>";

while($row = mysql_fetch_array($result))
  {
  echo "<tr>";
  echo "<td>" . $row['Name'] . "</td>";
  echo "<td><img src='" . $row['Pic']  . "' height='119' width='148' /></td>";
  echo "<td>" . $row['Description'] . "</td>";
  echo "<td>" . $row['Price'] . "</td>";
  echo "<td><a href="cart.php?action=add&id='".$row['id']."'>Add to cart"</a></td>";
  echo "</tr>";
   }
echo "</table>";

mysql_close($conn);
?>

the error are:

Parse error: syntax error, unexpected T_STRING, expecting ',' or ';'

[ZABI]

<?php 
$q=$_GET["q"]; 

include("connection.php"); 

$sql="SELECT * FROM menu WHERE Category = '".$q."'"; 

$result = mysql_query($sql); 

echo "<table border='1'> 
<tr> 
<th>    Menu    </th> 
<th>    Image    </th> 
<th>    Descriptions    </th> 
<th>    Price (RM)    </th> 
</tr>"; 

while($row = mysql_fetch_array($result)) 
  { 
  echo "<tr>"; 
  echo "<td>" . $row['Name'] . "</td>"; 
  echo "<td><img src='" . $row['Pic']  . "' height='119' width='148' /></td>"; 
  echo "<td>" . $row['Description'] . "</td>"; 
  echo "<td>" . $row['Price'] . "</td>"; 
  echo "<td><a href='cart.php?action=add&id=".$row['id']."'>Add to cart</a></td>"; 
  echo "</tr>"; 
   } 
echo "</table>"; 

mysql_close($conn); 
?>

[stepbystep]

oo..thanks..it works..