Replace with Dynamic variable in preg_replace

[MarPlo]

Hi
I'm trying the following code:

$t = '12<-- AB_C -->';
$AB_C = 'abc';
echo preg_replace('/\<-- ([A-Z_]+) --\>/', "$$1", $t);

I want to get "12abc" , but it outputs: 12$AB_C , so, it not recognize the replacement as dynamic variable.
Is it any way to use the matched word in preg_replace() as a variable, or dynamic variable?

[hyperionXS]

Use replace() instead

	$t = '12<-- AB_C -->';
	$AB_C = 'abc';
	alert( $t.replace(/<-- AB_C -->/i, $AB_C) )

[MarPlo]

Use replace() instead

	$t = '12<-- AB_C -->';
	$AB_C = 'abc';
	alert( $t.replace(/<-- AB_C -->/i, $AB_C) )

Hi
alert() is not in PHP, your example is wrong.
AB_C is not known, it is got with regexp.

[hyperionXS]

Oh, sorry, I thought it was JavaScript.
For PHP use str_replace

   $t = '12<-- AB_C -->';
   $AB_C = 'abc';
   echo str_replace('<-- AB_C -->', $AB_C, $t)

[MarPlo]

For those who look for a solution to this problem, the '/e' flag, which evalates the replacement, solved the problem, and returns the results i want, using:

preg_replace('/\<-- ([A-Z_]+) --\>/e', "$$1", $t);