www.webdeveloper.com
Results 1 to 3 of 3

Thread: [RESOLVED] MySQL Data - date and time to PHP

  1. #1
    Join Date
    Feb 2012
    Posts
    30

    resolved [RESOLVED] MySQL Data - date and time to PHP

    Hello,

    I'm wondering if anyone can help me.

    I have a countdown clock which has the following fields i need to populate

    code:
    --------------
    var year= ;
    var month= ;
    var day= ;
    var hour= ;
    var minute= ;

    I have created a date and time field in MySQL called 'ShowDateTime' and this field will contain different dates and times depending on the session userid $_SESSION['userid'].

    i have tried the following code which works by populating the fields, although it shows the words NaN (Not a Number) on view.

    code:
    --------------
    <? $isyr=mysql_fetch_array(mysql_query("SELECT EXTRACT(YEAR FROM ShowDateTime) FROM bookings WHERE userid='$_SESSION[userid]'"));

    $ismth=mysql_fetch_array(mysql_query("SELECT EXTRACT(MONTH FROM ShowDateTime) FROM bookings WHERE userid='$_SESSION[userid]'"));

    $isdd=mysql_fetch_array(mysql_query("SELECT EXTRACT(DAY FROM ShowDateTime) FROM bookings WHERE userid='$_SESSION[userid]'"));

    $ishr=mysql_fetch_array(mysql_query("SELECT EXTRACT(HOUR FROM ShowDateTime) FROM bookings WHERE userid='$_SESSION[userid]'"));

    $ismin=mysql_fetch_array(mysql_query("SELECT EXTRACT(MINUTE FROM ShowDateTime) FROM bookings WHERE userid='$_SESSION[userid]'")); ?>

    var year=<? echo $isyr; ?>;
    var month=<? echo $ismth; ?>;
    var day=<? echo $isdd; ?>;
    var hour=<? echo $ishr; ?>;
    var minute=<? echo $ismin; ?>;



    How can i make is so when i extract the date and time into the required fields, it brings through the numbers not text? or NaN.

    Hope this makes sense.

    Many Thanks
    Last edited by thewebportfolio; 02-20-2012 at 05:58 PM.

  2. #2
    Join Date
    Jul 2010
    Location
    /ramdisk/
    Posts
    865
    PHP Code:
    list($isyr,$ismth,$isdd,$ishr,$ismin) = mysql_fetch_row(
        
    mysql_query(
            
    sprintf("
                SELECT 
                  YEAR(ShowDateTime),
                  MONTH(ShowDateTime),
                  DAY(ShowDateTime),
                  HOUR(ShowDateTime),
                  MINUTE(ShowDateTime)
                FROM bookings 
                WHERE userid='%s'"
    ,
                
    mysql_real_escape_string($_SESSION[userid]))));

    print<<<EOJ
    var year={$isyr};
    var month=(
    $ismth};
    var day=
    {$isdd};
    var hour=
    $ishr};
    var minute=
    {$ismin};
    EOJ; 
    Your problem is you are not converting the array from mysql_fetch_array/*big hint right there*/() into an integer correctly. The array you are converting to an integer really holds the interger it is that you want.

    PHP Code:
    $month = array(12);
    echo 
    $month#wrong
    echo $month[0]; #correct, the values are indexed starting at 0. 
    Last edited by eval(BadCode); 02-20-2012 at 08:37 PM.
    I use (, ; : -) as I please- instead of learning the English language specification: I decided to learn Scheme and Java;

  3. #3
    Join Date
    Feb 2012
    Posts
    30
    Thank you Extremely grateful for this! Working like a dream!

Thread Information

Users Browsing this Thread

There are currently 1 users browsing this thread. (0 members and 1 guests)

Tags for this Thread

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •  
HTML5 Development Center



Recent Articles