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Thread: Create an array and it throws a parse error, wha?

  1. #1
    Join Date
    Jun 2006
    Location
    Under your bed
    Posts
    357

    Create an array and it throws a parse error, wha?

    If I try this:
    PHP Code:
    $sue = array(); 
    Or This:
    PHP Code:
    $sue['red'] = 2
    Or Even This:
    PHP Code:
    $sue = array();
    $sue['red'] = 2
    I get this error:
    Parse error: syntax error, unexpected T_VARIABLE in C:\xampp\htdocs\xampp\site\index2.php on line 4

    Why?
    The better I get at programming, the more I appreciate arrays. Handy dandy things they are.

  2. #2
    Join Date
    Aug 2004
    Location
    Ankh-Morpork
    Posts
    19,322
    Most likely something wrong with the preceding command, such as a missing terminal semicolon.
    "Please give us a simple answer, so that we don't have to think, because if we think, we might find answers that don't fit the way we want the world to be."
    ~ Terry Pratchett in Nation

    eBookworm.us

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