Assigning GET var to regular var.

[DaveRich]

I am having a strange issue that I think may be a syntax problem but I dont understand completely.

Here is my code:

    if(isset($_GET['famType']))
    {
        $famTypeStr = $famTypes[$_GET['famType']];
        echo "<script>alert('famType: " . $_GET['famType'] . " | " . $famTypeStr . "')</script>"; //DEBUG
    }

    if(isset($_GET['geo']))
    {
        $subgeoStr = $_GET['geo'];
        echo "<script>alert('geo: " . $_GET['geo'] . " | " . $famTypeStr . "')</script>";    //DEBUG
    } 

I am requesting the page containing the above code passing the get parameters as follows: ../page.php?famType="M01"&geo="2"

The alert box pops up for both if statements and it prints the contents of the get variables as desired, but both $famTypeStr and $subgeoStr are null.

Is there something wrong with the assignment syntax I'm using in these cases?

[DaveRich]

One bit of info I may have forgot to add,

the $famTypes array which is referenced in the assignment of "$famTypeStr" is defined as follows:

$famTypes = array(
     "M01" => "X01 - First family",
     "M02" => "X02 - Second Family",
); 

[tracknut]

Have you tried passing the parameters without quotes, like:

../page.php?famType=M01&geo=2

Dave

[DaveRich]

That does work! Thanks!

So in PHP is there any difference between passing an integer 2 and a string "2"?

[ScottyBoy]

You should also check that $_GET['famType'] is a key in $famTypes before attempting to use them together.

<?php
    error_reporting(-1);

    $famTypes = array(
        "M01" => "X01 - First family",
        "M02" => "X02 - Second Family",
    ); 

    if(!empty($_GET['famType']) && array_key_exists($_GET['famType'], $famTypes))
    {
        $famTypeStr = $famTypes[$_GET['famType']];
        echo "<script>alert('famType: " . $_GET['famType'] . " | " . $famTypeStr . "')</script>"; //DEBUG
    }

    if(!empty($_GET['geo']) && !empty($famTypeStr))
    {
        $subgeoStr = $_GET['geo'];
        echo "<script>alert('geo: " . $_GET['geo'] . " | " . $famTypeStr . "')</script>";    //DEBUG
    }

[tracknut]

That does work! Thanks!

So in PHP is there any difference between passing an integer 2 and a string "2"?

I'm pretty sure when you passed it with the quotes, all 3 characters - quote 2 quote - were in the string, and of course that's not what you were expecting. Attributes in query strings aren't quoted, that's just the way it works, and they end up as strings in the $_GET array.

Dave

[DaveRich]

Thanks for all the help and information. It is very much appreciated.