I do i make this code add up the rolls in the score

[newPro]

I am trying this snake eye game using recursive method. The problem is i could not make it add the two rolls. Help would be appreciated. Hereis the code:

function rollSingleDice(){

return Math.floor(Math.random()*6+1);
}

function rollDice(){
var playerScore = 0;
var die1 = rollSingleDice();
var die2 = rollSingleDice()

playerScore = playerScore + die1 + die2;
console.log("Die 1: " + die1+" Die 2: "+
die2+ " Score "+playerScore);
if (die1 !== die2){
return;
}else {
console.log("Congratulations Double Thrown!");
return rollDice();
}
}

rollDice();

[LutinFou]

I have just run your code replacing console.log with document.write to display the results on the screen and your code works fine for me. (i.e. it displays the reults of each individual roll and the sum of both rolls. If it is not working for you, maybe there is an error elsewhere in your code?
best regards
LF

[newPro]

I have just run your code replacing console.log with document.write to display the results on the screen and your code works fine for me. (i.e. it displays the reults of each individual roll and the sum of both rolls. If it is not working for you, maybe there is an error elsewhere in your code?
best regards
LF

I tried the document.write in the codecadey and it sort of stucks. When i use console log, the code return the score for each roll while i was expecting the second score to be a total of the two rolls during a double.

[xelawho]

assuming that you get another throw if you roll a double after rolling a double...

<script type="text/javascript">
var prevScore = 0;
function rollSingleDice(){
return Math.floor(Math.random()*6+1);
}

function rollDice(){
var die1 = rollSingleDice();
var die2 = rollSingleDice();
var score=die1 + die2;
console.log("Die 1: " + die1+" Die 2: "+
die2+ " Score "+Number(score+prevScore));
if (die1 == die2){
console.log("Congratulations Double Thrown!");
prevScore=prevScore+die1 + die2; 
rollDice();
	}
}

rollDice();
</script>

[newPro]

assuming that you get another throw if you roll a double after rolling a double...

<script type="text/javascript">
var prevScore = 0;
function rollSingleDice(){
return Math.floor(Math.random()*6+1);
}

function rollDice(){
var die1 = rollSingleDice();
var die2 = rollSingleDice();
var score=die1 + die2;
console.log("Die 1: " + die1+" Die 2: "+
die2+ " Score "+Number(score+prevScore));
if (die1 == die2){
console.log("Congratulations Double Thrown!");
prevScore=prevScore+die1 + die2; 
rollDice();
	}
}

rollDice();
</script>

Thanks xelawho:
That cetainly fixed the problem. I have a question though about the solution you proposed. Which references to die1 and die2 actually call the random number generator? My first thought about your solution is the last call to rollDice() in the if statement would call the roll for a third time? I would appreciate to get some explanation around this point.