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Thread: Dynamic field searches

  1. #1
    Join Date
    Feb 2010
    Location
    Grantham, UK
    Posts
    103

    Dynamic field searches

    Hi. I am trying to save myself some coding and am thinking an array would help.

    I have 5 tables in database called plan1, plan2 etc.. with each one having 9 columns (tot1, tot2, tot3, tot4, etc..)

    I am wondering if there is a way to do something like the following :

    Code:
    $c=1;
    	require("connectdb.php");
    while ($c <= 9)
    {
    	$u=$_SESSION[refs][$c-1];
    	$result = mysql_query("SELECT * FROM plan.$_SESSION[plan]
    	WHERE userid = '$u' LIMIT 1");
    	while($row = mysql_fetch_array($result))
    	{
    		$_SESSION[rlvltot][$c-1]=$row['tot.$c'];
    	}
    	$c++;
    }
    	mysql_close($con);
    where $_SESSION[plan] says which table to use and $c is which total to get.

    This would save me writing out the same script 9 times.

    Any hints you can give on how to achieve this would be great!

  2. #2
    Join Date
    Feb 2010
    Location
    Grantham, UK
    Posts
    103
    have been working on a few ideas about linking strings together, and have come across a related problem...

    when adding a new member, i am using the following (shortened for viewing):

    Code:
    <?php
    -----part1-----
    		require("connectdb.php");
    		$sql = "INSERT INTO members (email, password, plannum)
    		VALUES
    		('$_SESSION[email]','$_SESSION[userpass]','$_SESSION[plan]')";
    		if (!mysql_query($sql,$con))
    		{ die('Error: ' . mysql_error()); }
    		mysql_close($con);
    
    -----part2-----
    		require("connectdb.php");
    		$result = mysql_query("SELECT * FROM members
    			WHERE email = '$_SESSION[email]' AND password = '$_SESSION[userpass]' LIMIT 1");
    		while($row = mysql_fetch_array($result))
    		{
    			$_SESSION[userid] = $row['userid'];
    		}
    		mysql_close($con);
    
    
    -----part3-----
    		$c=1;
    		while ($c <= 5)
    		{
    			$newplan="plan".$c;
    
    			require("connectdb.php");
    			$sql = "INSERT INTO $newplan (userid, email)
    			VALUES
    			('$_SESSION[userid]', '$_SESSION[email]')";
    			if (!mysql_query($sql,$con))
    			{ die('Error: ' . mysql_error()); }
    			mysql_close($con);
    
    		}
    ?>
    Part 1 puts the member into the database. working fine.
    Part 2 gets the user id of the member. also working fine.
    part 3 is similar to original query. Am attempting to save putting same code 5 times for tables plan1, plan2, plan3, plan4 and plan5.

    Upon running, I get
    Error: Duplicate entry '1057' for key 'PRIMARY'
    Looking at the database, the table plan1 is written, none of the other plans are, and strangely, there is a duplicate appearing in the members db.

    Again, i am happy to type same script up 5 times for each plan, but still would really appreciate knowing why this has gone wrong. Thanks.

  3. #3
    Join Date
    Feb 2010
    Location
    Grantham, UK
    Posts
    103
    ok..silly answer for that, I forgot the c++ at the end, so that part is working, though am still getting two entries in the members db now :/

  4. #4
    Join Date
    Feb 2010
    Location
    Grantham, UK
    Posts
    103
    UPDATE:

    I have changed my code substantially and tidied it up. Please ignore all previous coding.

    It is now as follows -

    Code:
    <?php
    	$newplan="plan".$_SESSION[plan];
    	$g=0;
    	while ($g <= 8)
    	{
    		$h=$g+1;
    		$w=$_SESSION[refs][$g];
    		$lnt="lvl".$h."tot";
    		$lnn="lvl".$h."new";
    		
    		$test=mysql_query("UPDATE $newplan SET $lnt = $lnt+1, $lnn = $lnn+1, plantot = plantot+1, plannew = plannew+1
    			WHERE userid = '$w' LIMIT 1");
    
    		$qqq=mysql_query("UPDATE members SET tokens = tokens+1, newtokens = newtokens+1
    			WHERE userid = '$w' LIMIT 1");
    
    		echo "newplan is ".$newplan.". lnt is ".$lnt.". lnn is ".$lnn.". plantot is ".plantot.". plannew is ".$plannew.". w is ".$w;
    		echo "<br /> test is ".$test."<br />";
    		echo "<br /> qqq is ".$qqq."<br />";
    		
    		$g++;
    	}
    ?>
    I am still getting the same error though. "qqq" always passes and adds data as expected.
    "test" will still only update the table when $_SESSION[plan] = 1. Never when 2 or above.

    Does anyone have any ideas at all?

  5. #5
    Join Date
    Mar 2006
    Location
    Discworld
    Posts
    75
    and why it should change?
    You have it as a static variable:
    $newplan="plan".$_SESSION[plan];
    before (outside) of the loop.
    So any changes happen inside loop does not matter for that variable.
    Try this one:
    HTML Code:
    <?php	
    	$g=0;
    	$h=0;
    	while ($g <= 8)
    	{
    
    		$h=$h+1;
    		$newplan="plan".$h;
    		$w=$_SESSION[refs][$g];
    		$lnt="lvl".$g+1."tot";
    		$lnn="lvl".$g+1."new";
    		
    		$test=mysql_query("UPDATE $newplan SET $lnt = $lnt+1, $lnn = $lnn+1, plantot = plantot+1, plannew = plannew+1
    			WHERE userid = '$w' LIMIT 1");
    
    		$qqq=mysql_query("UPDATE members SET tokens = tokens+1, newtokens = newtokens+1
    			WHERE userid = '$w' LIMIT 1");
    
    		echo "newplan is ".$newplan.". lnt is ".$lnt.". lnn is ".$lnn.". plantot is ".plantot.". plannew is ".$plannew.". w is ".$w;
    		echo "<br /> test is ".$test."<br />";
    		echo "<br /> qqq is ".$qqq."<br />";
    		
    		$g++;
    	}
    ?>
    Last edited by alexsts; 06-08-2012 at 02:44 PM.

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