help return max number

[Foolly]

when you pass an argument full of numbers into a function, how do you make the function return the largest number in the arguments? please i need this explained without the function actually defining/declaring any of the arguments/parameters in its parenthesis

[rtrethewey]

Try the Math.max() function.

[Foolly]

ah yes i know the Math.max ... but for educational purposes beause im new to JS, i wanted to know how it was done this way. or is it not practical?

[Logic Ali]

ah yes i know the Math.max ... but for educational purposes beause im new to JS, i wanted to know how it was done this way. or is it not practical?

You use the arguments property, which you can research.

[Foolly]

You use the arguments property, which you can research.

i have but i cant get it working. i can only get it working when i reference the arguments in my function call. but i want a way to do this without defining parameters, incase the arguments passed into the function exceeds the function parameters. heres what i mean

onclick="values(3,6,8);" will be passed to my function which is ready for them: function values(a,b,c).
but what if my function wasnt ready, i.e more arguments where passed, like values(3,6,8,24,4) and their length exceeded my function parameters? i want a way to make the function be able to handle this and still work out the max number.

im happy with the Math.max method but i would just like to see how this is done

[toicontien]

The arguments object in a function is an Array-like object. It has a length property telling you how many arguments the function currently has passed in. You can also access each argument in array syntax:

arguments[0]
arguments[1]

[SparoHawk]

You have cycle the numbers and compare.

Simple example:

<script type="text/javascript">
function maxNumber()
{
    var max = '';
    for(var i in arguments)
    {
        if(arguments[i] > max)
            max = arguments[i];
    }
    
    alert(max);
}

maxNumber(1, 8, 5, 9, 3, 2);
</script>