using input type="button" does not work with if(isset($_POST['button-name']))

[toptomato]

Here's something i was trying tonight.

A form with 3 buttons(!).
I kept all 3 in the same <form> element just to see,...

the first button, submit works as expected,
using

if(isset($_POST['submit'])) 

the second button at first i had coded like this:

<input type="button" name="reset-page-copy" value="reset to default" /> 

when coded as type="button" it did not respond to this...

if(isset($_POST['reset-page-copy'])) {
//run some code
} 

but when coding as type="submit" or .....

<input type="submit" name="reset-page-copy" value="reset to default" /> 

...the if isset statement worked.

why is that?? i never came across this before.
and how can i use input type="button" instead of input type="submit" ??

big thanks everyone

[NogDog]

You could add a type="hidden" input element to check for.

[toptomato]

thanks but not sure what you mean. check for what?,

it's not critical of course, i can use input type="submit" instead of input type="button" but am curious why,... what that difference is,

[NogDog]

Frankly, I've never used type="button", so I'm not sure if you are encountering a browser-specific problem or a general HTML issue. What does a button-type provide for you that a submit-type does not? Alternatively, you could use a button element with type="submit", perhaps?

[captainscall]

i don't think buttons get 'set'. They're just there, see?

What you need is something like was_pressed($_POST[your_button])

So PHP doesn't really deal with that as far as I know. You can use javascript:

<input type="button" name="mybutton" id="mybutton" onclick="dostuff()" />

<script language="javascript">
function dostuff()
{
// the code you want done when the button gets clicked
}
</script>


By the way there is an <input type="reset" ... /> that will reset all fields in the form to their original values FOR you, if you didn't know

[toptomato]

thanks guys.