beginer quastion (return won't work)

[jibbo]

if i use return i; it only gives me the result of 1, but when i use console.log(i) it goes thru the whole list can would be helpful if someone please explain why it isn't working ?

var loop = function(){
  
  for( var i = 1; i < 100; i++ ){
  if(i % 5 ===  0 || i % 7 === 0){
  
  } else {
  console.log(i) ;
  }
  }         

};

loop();

[nap0leon]

Your function does not include "return i" anywhere in it.
I presume you mean for it to look like this:

<script type="text/javascript">
var loop= function() {
	for( var i = 1; i < 100; i++ ){
		if(i &#37; 5 ===  0 || i % 7 === 0){
			return i;
		} else {
			//document.write('False '+i+'<br>') ;
		}
	}         
};

document.write(loop());
</script>

[criterion9]

"return" exits the function completely and doesn't continue executing the loop....console.log only appends your content to the console and doesn't exit the function at all...

[jibbo]

@nap0leon: I know, i meant it in place of console.log, however that is not the idea, the idea is to print the whole number list and skip those divisable by 5 and 7, the console.log(i) did it correct but i was just trying to understand return and why it didn't work.
i'am testing it on codeacademy's console by the way.
thanks


@criterion9: Really ? i didn't find that info in any reference for return, anyway thanks for clearing THAT up, know where i can find more info about it ?

[jibbo]

Also found this now
https://developer.mozilla.org/en/Jav...tements/return

[jibbo]

@nap0leon: I know, i meant it in place of console.log, however that is not the idea, the idea is to print the whole number list and skip those divisable by 5 and 7, the console.log(i) did it correct but i was just trying to understand return and why it didn't work.
i'am testing it on codeacademy's console by the way.
thanks


@criterion9: Really ? i didn't find that info in any reference for return, anyway thanks for clearing THAT up, know where i can find more info about it ?

[bionoid]

If you want to return the entire list of numbers, you would have to pass back an array (or if you want to use a string, but that isn't as useful):

function loop()
{
	var list = [], i;
	for (i = 1; i < 100; ++i) {
		if (i &#37; 5 && i % 7) {
			list.push(i);
			console.log(i);
		}
	}
	return list;
}

alert(
	loop()
);