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Thread: not creating foreign kye table please help me

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  1. #1
    Join Date
    Nov 2012
    Posts
    20

    not creating foreign kye table please help me

    hii friends

    i am trying to retrieve data from table but at the time of running that code server showing following error mysql_fetch_array() expects parameter 2 to be long, resource given in C please let me know my mistake ....


    my code is here:

    <?php
    $dbhost='localhost';
    $dbuser='root';
    $dbpass='';
    $conn=mysql_connect($dbhost,$dbuser,$dbpass);
    $sql="SELECT option1 FROM quiz ORDER BY RAND() LIMIT 10";
    mysql_select_db("goget");
    $retval=mysql_query($sql) or die(mysql_error());
    while ($r=mysql_fetch_array($retval,$conn))
    {
    echo $r['option1']."<br/>";
    }
    ?>

  2. #2
    Join Date
    Jul 2007
    Location
    Wisconsin
    Posts
    468
    From php.net

    Quote Originally Posted by Description

    array mysql_fetch_array ( resource $result [, int $result_type = MYSQL_BOTH ] )
    Quote Originally Posted by Parameters

    result

    The result resource that is being evaluated. This result comes from a call to mysql_query().

    result_type

    The type of array that is to be fetched. It's a constant and can take the following values: MYSQL_ASSOC, MYSQL_NUM, and MYSQL_BOTH.

    PHP Code:
    $retval=mysql_query($sql$conn) or die(mysql_error());
    while (
    $r=mysql_fetch_array($retval,MYSQL_BOTH))
    {
    echo 
    $r['option1']."<br/>";


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