Basically the above code works but only if the user then puts "http://example.com/feed.php?id=3"Code:<?php mysql_connect ('localhost', 'root', 'password') ; mysql_select_db ('manchesternews'); if (!isset($_GET['id']) || !is_numeric($_GET['id'])) { die("Invalid ID specified."); } $id = (int)$_GET['id']; $sql = "SELECT * FROM newsreel WHERE id='$id' LIMIT 1"; $result = mysql_query($sql) or print ("Error has incurred. Please look at your code.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $articletitle = ($row['articletitle']); $article = ($row['article']); ?> <p><strong><?php echo $articletitle; ?></strong><br /><br /> <?php echo $article; ?><br /><br /> <hr /></p> <?php }
They have to type ?id=3 in.
Is it possible on the feed.php to have the $articletitle displayed and when that is clicked it gets the "id=3" which loads the "fee.php?id=3" Thanks.


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