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Thread: Calculate distance with variable lat and lon values

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  1. #1
    Join Date
    Jun 2007

    Calculate distance with variable lat and lon values


    I have a problem with implementing variables into a function that calculate distance between 2 latitudes, longitudes.
    One of them is constant, and the second one being passed from the form.

    Here is the code:

    PHP Code:
    $lon1 $_POST['lon1'];
    $lat1 $_POST['lat1'];
    $lon2 '-0.30020239';
    $lat2 '51.58734910';
    distance($lat11$lon11$lat22$lon22) { 
    $theta $lon11 $lon22
    $dist sin(deg2rad($lat11)) * sin(deg2rad($lat22)) +  cos(deg2rad($lat11)) * cos(deg2rad($lat22)) * cos(deg2rad($theta)); 
    $dist acos($dist); 
    $dist rad2deg($dist); 
    $miles $dist 60 1.1515;

    //////////  return good calculation
    echo distance(52.611644, -0.2630451.58734910, -0.30020239) . " miles<br>";

    ////////// my way - return wrong calculation 
    echo distance("$lon1""$lat1"51.58734910, -0.30020239) . " miles<br>"
    As long as i have lat, lon values hardcoded is fine, but idea is to have this calculation done from variables.
    Both will vary .... tried different configurations ... i'm losing it ...

    How should I code it ??

    Thanks for your help in advance!

  2. #2
    Join Date
    Aug 2004
    Looks like you have your latitude and longitude parameters transposed when you call your distance() function. (It's defined as lat, long, lat, long, but you've called it as long, lat, log, lat.)
    "Please give us a simple answer, so that we don't have to think, because if we think, we might find answers that don't fit the way we want the world to be."
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  3. #3
    Join Date
    Jun 2007
    wow, how could i not see that .. blind ... works perfect.

    Thank you for opening my eyes.

    Last edited by nitapita; 01-06-2013 at 03:01 AM.

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