how to convert string in YYMMDD format to DD/MM/YY format

[srinuetta]

Hi
I have string in YYMMDD format but i need to convert to DD/MMYY format please let me know is there any built in fuctions available in javascript api

ex:130122 to 22/01/13
Please help me

Thanks
Srinivasula Reddy

[ReFreezed]

You can use string.substr() to extract parts of a string. Just cut up your date string and put it together in the order you want.

[JMRKER]

Possible alternative...

<script type="text/javascript">
String.prototype.toMMDDYY = function(sep) {  // expects input format of YYMMDD to convert to MM/DD/YY
  return this.substr(2,2)+sep+this.substr(4,2)+sep+this.substr(0,2)
}

// if short year IS KNOWN TO BE in this century
String.prototype.toMMDDYYYY = function(sep) {  // expects input format of YYMMDD to convert to MM/DD/YYYY
  var tdate = this;
  return this.substr(2,2)+sep+this.substr(4,2)+sep+'20'+this.substr(0,2)
}

// whoops ... mis-read original request
String.prototype.toDDMMYY = function(sep) {  // expects input format of YYMMDD to convert to DD/MM/YY
  return this.substr(4,2)+sep+this.substr(2,2)+sep+this.substr(0,2)
}

// test of above
var str = '130125';  alert(str+' converts to '+str.toMMDDYY('/')+' or '+str.toMMDDYYYY('/')+' or '+str.toDDMMYY('/'));
    str = '121225';  alert(str+' converts to '+str.toMMDDYY('-')+' or '+str.toMMDDYYYY('-')+' or '+str.toDDMMYY('-'));
</script>

[007Julien]

Or simply, with a regular expression :

var today="130126";
var todayNewFormat=today.replace/(\d\d)(\d\d)(\d\d)/,'$3/$2/$1');
alert(todayNewFormat);//=>26/01/13

;

[JMRKER]

Or simply, with a regular expression :

var today="130126";
var todayNewFormat=today.replace/(\d\d)(\d\d)(\d\d)/,'$3/$2/$1');
alert(todayNewFormat);//=>26/01/13

;

Nice, but I think you left out one '(' character ...

var today="130126";
var todayNewFormat=today.replace(/(\d\d)(\d\d)(\d\d)/,'$3/$2/$1');
alert(todayNewFormat);//=>26/01/13

[007Julien]

Sorry Srinuetta... Thanks JMRKER !
We must write :

var todayNewFormat=today.replace(/(\d\d)(\d\d)(\d\d)/,'$3/$2/$1');

[rnd me]

one simple way:

   "yymmdd".split(/(.{2})/).reverse().join("")