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Thread: SCRIPT5007: Unable to get property '1' of undefined or null reference

  1. #1
    Join Date
    Jun 2013
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    1

    SCRIPT5007: Unable to get property '1' of undefined or null reference

    i have a error in my console
    SCRIPT5007: Unable to get property '1' of undefined or null reference
    i am unable to solve this error please help me!!!


    // Internet Explorer
    if ( sAgent.indexOf("msie") != -1 && sAgent.indexOf("mac") == -1 && sAgent.indexOf("opera") == -1 )
    {
    var sBrowserVersion = navigator.appVersion.match(/MSIE (.\..)/)[1] ;
    return ( sBrowserVersion >= 5.5 ) ;
    }

  2. #2
    Join Date
    Mar 2007
    Location
    U.K.
    Posts
    1,127
    Quote Originally Posted by javedusmani2 View Post
    Code:
             var sBrowserVersion = navigator.appVersion.match(/MSIE (.\..)/)[1] ;
    That statement assumes that there will always be a match. If there isn't then there's an error.

    Code:
    var sBrowserVersion = ( sBrowserVersion = navigator.appVersion.match(/MSIE (.\..)/) ) ? sBrowserVersion[1] : 0;
    Better yet, as anyone will tell you - don't perform unreliable browser detection.

  3. #3
    Join Date
    May 2006
    Location
    Somewhere behind your screen
    Posts
    1,653
    why not just check for 'document.all' ?

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