Gooed evening;

Im new with php and i got some application that i create as learn proces.

But nog i have an problem. and i can't solve :s

Im trying to edit one row on mij sql data. But if i do the data of all rows would be edited. And that not my intention i want to update that one specific row. Plz help me!

http://st-joris-turnhout.be/man/log-ins-test.php a working example of the bug.

code:

my database:
Code:
CREATE TABLE IF NOT EXISTS `logins` (
  `ID` int(11) NOT NULL AUTO_INCREMENT,
  `Website_applicatie` varchar(150) NOT NULL,
  `Login` varchar(150) NOT NULL,
  `Pass` varchar(150) NOT NULL,
  `Notitie` varchar(255) NOT NULL,
  PRIMARY KEY (`ID`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=35 ;
function:
PHP Code:
$id =$_REQUEST['ID'];

$result mysql_query("SELECT * FROM logins WHERE ID  = '$id'");
$row mysql_fetch_array($result);
if (!
$result
        {
        die(
"Error: Data is niet gevonden");
        }

                
// Laad de bestaande data in de form
                
$web_app=$row['Website_applicatie'] ;
                
$login=$row['Login'] ;                    
                
$pass=$row['Pass'] ;
                
$notitie=$row['Notitie'] ;
                
$weblink=$row['Hyperlink'];

if(isset(
$_POST['save']))
{    
    
// Wijzigd de data
    
$web_app_save $_POST['webapp'];
    
$login_save $_POST['login'];
    
$pass_save $_POST['pass'];
    
$notitie_save $_POST['notitie'];
    
$hyperlink_save $_POST['hyperlink'];

    
mysql_query("UPDATE logins SET Website_applicatie ='$web_app_save', Login ='$login_save', Pass ='$pass_save', Notitie ='$notitie_save', Hyperlink ='$hyperlink_save'")
                or die(
mysql_error()); 
    echo 
"Uw wijziging is doorgevoerd!";
    
    
header("Location: ../log-ins-test.php");            
}
mysql_close();
?> 
trigger:
HTML Code:
<a class="label label-default" href="includes/edit.php?ID=129"><span class="glyphicon glyphicon-pencil"></span> Edit</a>
.

I hiope u can help me guys