list

[sandro27]

Hi all!!

I am trying to display a vertical list from a database but I would like advice how to do it.

My database has the following fields:
facilites_id

Hotel_id

list_facilities - Here is where the data list is stored (swimming pool, restaurant, bar, etc)


I would like to disply this data in a vertical list like this:
# Breakfast Included
# Restaurant
# Internet Access
# Airport Pick Up
# etc

Unfortunately the words come in sequence.

Maybe my table design is weak. I could try the yes/no but I don´t know how to do it.

Any suggestions

sandro27

[ray326]

Mark it up using an unordered list: <ul><li></li>...</ul>.

[the tree]

Just what ray said, start with this:

<ul>
<li>Breakfast included</li>
<li>Resturant</li>
<li>Et Cetera</li>
</ul>

Then tame those lists and you'll be sorted.

[sandro27]

Thanks guys. However I another problem.

Let´s say I have 2 tables:

facilities ( facilities_id, facilities_name)
hotel_facilities ( hotel_id, facilities_id)

I am trying to get data from this tables with sql

include "intro.php";
$sql1="select * from hotel_facilities,facilities where 
facilities.facilities_id=hotel_facilities.facilities_id
and acc_id=    '$acc_id' order by facilities_name";
$busca1=mysql_query($sql1,$conexao) or die(mysql_error());
$lista1=mysql_fetch_array($busca1); 

then I show like this

<?
while($lista1=mysql_fetch_array($busca1)){
?>
<ul></ul><li><?=$lista1['facilities_name']?></li>
<?
}
?>

The problem is that this doesn´t show all data in the table, always missing one.

Wonder why and appreciate any help

sandro24

[ray326]

Sorry. I'm not a PHP guy but one will come along I'm sure.

[saji]

Hello,

You have to remove the following line from the script.
"$lista1=mysql_fetch_array($busca1);" which is under
"$busca1=mysql_query($sql1,$conexao) or die(mysql_error()); ".

The reason is, mysql_fetch_array would skip one row.

Hope this will help you.

Regards,
Saji John

[sandro27]

Hi Saji.

It worked perfectly. Thanks. The good be with you in 2005.

sandro27