simple perl script

[2muchtime]

Hey I m just starting to learn some perl, this may not be a good script, but i am wondering where my errors are, and how I can improve it.

#!usr/bin/perl

$c = 10;

print "\nType something, and be amazed!\n";
$a = <STDIN>;
chomp $a;
print "you typed, \"$a\" WOW!\n";
#9
print "Now let's try something else!\n enter a number between -10 and 10\n";
$b = <STDIN>;
chomp $b;
#14
do
{
for ($c == -10,$c <= 10,$c++);
} while($b != $c);
if ($b != $c)
{
print "You didn't enter a value between -10 and 10! DO SO1\n";
$b = <STDIN>;
}
else
{
print "You entered $b\n";
$b **= 2;
print "When squared that equals $b\n";
print "is that true?\n";
$d = <STDIN>;
if ($d == yes)
{
print "Darn right it is!\n";
}
else
{
print "Liar!\n";
}
}

[Phil Karras]

Here's one problem:

#14
do {
  for ($c == -10,$c <= 10,$c++);
} while($b != $c);

if ($b != $c) {
  print "You didn't enter a value between -10 and 10! DO SO1\n";
  $b = <STDIN>;
}

If $b is not == $c your code never gets to the if($b != $c) section. Also, since you will forever do the do-while loop untill such time as $b == $c you don't need the if($b != $c) section at all.


Last, since you've made no provision for the person entering something NOT between -10 and 10 if they do enter something outside that range you will enter an infinite loop at your do-while statement.