Even + method

[NichoLe]

Good Afternoon all ...

Ive beeen trying this question out for 2 days now but no improvment i might be losing it or something ... can someone help

1- Create the class Even. It should contain two methods:

isEven: The method should take an integer argument and return true if the integer in even and false otherwise. The method should use the reminder operator to determine if the integer is even or not.

The main method should ask the user to input a number and it will call the isEven method to check if it is even or not. If the number is even the maid method will display "YOU ENTERED AN EVEN NUMBER" If the number is odd the mmain method should continue to ask the user to input numbers until he enters "0".



This is what i did

import javax.swing.JOptionPane;

class Even
{
    public static void main (String args[])
{

    String Num1;
    int number1, num;

    Num1= JOptionPane.showInputDialog("Enter a number: ");
    number1 = Integer.parseInt(Num1);
    
    isEven(num);
    
    System.exit( 0 );

}

    static void isEven(int a)
        {
        
        if ( a % 2 == 1)
    
            {
                JOptionPane.showMessageDialog(null, "You entered an even number " + a);
            }
       
        else if ( a % 2 == 0)
            {
                 JOptionPane.showMessageDialog(null, "You entered an odd number " + a);
            }
        
        
        }//isEven()
   }//end main

Please tell me if am on the wrong track!!

[Khalid Ali]

you are on right track except the following.
the variable u are passing to isEven(num) is not asigned any values yet, it should be

isEvent(number1);

(a%2)==0 means its even
(a%2)==1 means its odd

second in your main message you need to put a condition after you get input from user where you check for input, if its zero then u don't call isEven() method but close the program

something like this

     String Num1;
    int number1;
while(true){//run a loop for this to go for ever unless user enters 0
    Num1= JOptionPane.showInputDialog("Enter 0 (zero) to quit\nOr  Enter a number: ");
    number1 = Integer.parseInt(Num1);
    if(number<=0){
    //exit program here
    System.exit(0);
    }else{//process data
     isEven(number1);
    }
} 

[NichoLe]

Thank You bro ... Ill go with ur advice and reply 2 u soon

[NichoLe]

Hi ... i tried this

import javax.swing.JOptionPane;

class Even
{
    public static void main (String args[])
{
    
    String Num1; 
    int number1; 
    
    //run a loop for this to go for ever unless user enters 0 
    
    while(true)
    {

        Num1= JOptionPane.showInputDialog("Enter 0 (zero) to quit\nOr  Enter a number: "); 
        number1 = Integer.parseInt(Num1); 
        
            if(number1<=0)
            { 
            
            System.exit(0); 
            }
    
                else{ 
            isEven(number1); 
            } 
    }//end loop

    

    static void isEven(int a)
        {
        
        if ( a % 2 == 1)
    
            {
                JOptionPane.showMessageDialog(null, "You entered an odd number " + a);
            }
       
        else if ( a % 2 == 0)
            {
                 JOptionPane.showMessageDialog(null, "You entered an even number " + a);
            }
        
        
        }//isEven()
   }//end main

But the error i get is in this line

isEven(number1);

^^^ cannot resolve symbol method isEven (int)

[Khalid Ali]

that is because you have your isEven method/function in the main function.
bring it out of that

[NichoLe]

you mean i should not include it in the loop???

[Khalid Ali]

yep....because you have function call in the loop

[NichoLe]

it worked ... letz party

import javax.swing.JOptionPane;

class Even
{
   public static void main (String args[])
   {
       String Num1; 
       int number1; 

       //run a loop for this to go for ever unless user enters 0 
       while(true)
       {
           Num1= JOptionPane.showInputDialog("Enter 0 (zero) to quit\n" +
                                             "Or Enter a number: "); 
           number1 = Integer.parseInt(Num1); 

           if(number1<=0)
               System.exit(0); 
           else
               isEven(number1); 
       }//end loop
   }// end main

   static void isEven(int a)
   {
       if ( a % 2 == 1)
           JOptionPane.showMessageDialog(null, "You entered an odd number " + a);
       else if ( a % 2 == 0)
           JOptionPane.showMessageDialog(null, "You entered an even number " + a);
   }//isEven()
}//end class

[Khalid Ali]

yayyyyy...