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Thread: New page in servlets

  1. #1
    Join Date
    Sep 2005

    New page in servlets


    I have a servlet page. In that I have 2 fields like userName & userId.
    There is a submit button .When I press the submit button I should get a new Page with the entered details.Can any one tell me how to open new page & pass parameter to it . The first page is like this.

    import javax.servlet.ServletConfig;
    import javax.servlet.ServletException;
    import javax.servlet.ServletOutputStream;
    import javax.servlet.http.HttpServlet;
    import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServletResponse;

    public class FirstPage extends HttpServlet {

    protected void doGet(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException
    ServletOutputStream out = res.getOutputStream();
    out.println("<html><head><title>First page Form</title></head>");
    out.println("<body bgcolor =cccccc>");
    out.println("<form action = method = Post >");
    out.println("<center><h3><b>First page Form</b></h3><br><br><br>");
    out.println("<table border = 2>");
    out.println("<tr><td><b>User Name :</b></td><td><input type = text name = UserName></td></tr><tr><td>");
    out.println("<b>User Id :</b></td><td><input type = text name = UserId></td></tr>");
    out.println("<input type = submit value = Submit>");
    out.println("<input type = Reset value = Clear></tr></td>");
    String l_userName = req.getParameter("UserName");

    System.out.println("l_userName " + l_userName);


    public String getServletInfo()
    return "A Servlet";

    public void init(ServletConfig arg0) throws ServletException


    But how to know when button is pressed & it should open a new page & display all the values.

  2. #2
    Join Date
    Sep 2005
    Chicago, Il
    For something like this you should really be using a JSP instead of a servlet.

    In the JSP you would just write plain old HTML and use a form. Have that form point to you second page (or a servlet if you are doign processing, although it looks like you are just learning). In that other JSP you could just do a request.getAttribute(param_name) where param_name is the name of the form value form the previous page. So to print it out to the screen would be something like the following for your example:


    In a JSP the "out" and "request" object will automatically be given to you, you would not need to do any kind of import statement. JSPs were invented as a way to avoid writing HTML code in your servlets as you have in your example.

  3. #3
    Join Date
    Feb 2005
    out.println("<form action =\"Your URL destination\" method = Post >");

    Please assign your URL destination...
    Gw manusia yang punya kebiasaan yang tidak biasa...

  4. #4
    Join Date
    Sep 2005

    Thanks. It worked...

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